Re: relativity vs velocity addition


<lkoluk2003@xxxxxxxxx> wrote in message news:1166089679.248549.246580@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
|
| Sorcerer yazdi:
| > <lkoluk2003@xxxxxxxxx> wrote in message news:1165919683.448586.288430@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
| > | It seems that the assumption that the maximum distances between the
| > | twins during inbound and outbound part are equal is not generally true.
| > | I.e. the most general formula is t1=x1/v1 and t2=x2/v2 where x1 is not
| > | equal to x2. In this case, the only explanation is that the clock rates
| > | of both twins are the same even from the point of view of the twins.
| > |
| > | On the other hand, the relativity principle is fully compatible with
| > | this. I copied the following from my text in another threat.
| > | "Each tick in a clock is an event and an event's observed time can be
| > | different from time dilation. For example one can set a clock by using
| > | a light pulse
| > | and two mirrors.
| >
| > The second is the duration of 9 192 631 770 periods of the radiation corresponding to the transition between the two hyperfine levels of the ground state of the cesium 133 atom.
| >
| > http://physics.nist.gov/cuu/Units/second.html
| >
| > See anything about setting a counter with two mirrors?
| >
| > Send a caesium atom to Proxima Centauri and back, COUNTING transitions.
| >
| > The count will match an identical caesium atom that remains here.
| >
| > During the journey it will *appear* not to match due to
| >
| > transitions being "in flight", aka Doppler shift.
| >
| > There are no missing or additional counts, hence no count dilation,
|
| Ok. But what is the mechanism behind this light emmitting?

Strike a match. That emits light.


Does the
| frequency relate to distance/speed relation?

No, frequency relates to the inverse time law, f = 1/t.
Blind Poe can explain inverse laws to you.


| For example is the
| frequency proportional to (d1-d2)/(v1-v2) where d1&v1 is the radius of
| an orbital and the speed of an electron in this orbital respectively
| and d2&v2 is the radius&electron speed at the orbital where the
| electron drops to after it emits a photon?

No.

|
| >
| > hence no time dilation.
| >
| > Einstein was an idiot.
| >
|
| I don't think

Of course you don't. Nobody ever said you did. That's
why I have to tell you Einstein was an idiot, you can't work
it out for yourself. You are an idiot too, you CAN'T think.

| so.

Exactly.



| His mistake

If he made a mistake he was an idiot.

| was to assume the light speed is the same
| for all inertial frames


Einstein never said it was. That's your mistake.



| and the others vary respectively in the
| relation light speed=distance/duration. However, the relativity
| principle requires that the duration is the same for all inertial
| frames and the others vary respectively.


What relativity principle?

Read this, published in the British Journal of Theoretical Physics
http://www.androcles01.pwp.blueyonder.co.uk/PoR/PoR.htm


|
| Lokman Kolukisa
| >
| >
| >
| >
| >
| >
| >
| >
| >
| >
| >
| >
| >
| >
| > The pulse is reflected between the mirrors and the
| > | time interval between the reflection times of mirror 1 can be
| > | considered as one tick of this clock. If the light speed is source
| > | dependent then the duration of each tick is the same regardless of the
| > | speed of the clock and the time delation."
| > |
| > | Assume there is a platform with the clock mentioned above and two
| > | observers A&B. The tick time of this clock would be t=2.x/c where x is
| > | the distance between the mirrors.
| > |
| > | Now let the platform carrying the observer B is moving with a constant
| > | speed v with respect to the observer A. The clock is placed in such a
| > | way that the light pulse movement is in the same direction with the
| > | platform's speed. Assume there is a time dilation B. I.e. t'=t.B where
| > | t' is the time measured by observer B and t is the time measured by the
| > | observer A. Since according to the observer B, there is nothing
| > | changed, so (s)he will observe the tick time as t'=2x'/c or 2.x'=c.t'.
| > |
| > | The relativity principle requires that the light speed is source
| > | dependent. Let this relative speed is k(v). Then the tick time for
| > | observer A would be
| > | t=2.x'/k(v) = c.t'/k(v ) = c.t.B/k(v)
| > |
| > | >From here we deduce k(v)=B.c. On the other hand x'/t'=x/t must be true.
| > | I.e. x'=x.B. So from here
| > |
| > | t=2.x'/k(v) = 2.x.B/(c.B) = 2.x/c
| > |
| > | same with if the speed was zero. As seen the observed tick time is
| > | independent from the speed and from the dilation factor. The same thing
| > | is true for any event including the movement of someting or at least
| > | any event whose time is measured by distance/speed. This is a perfect
| > | result because the twin paradox is fully resolved now(assuming the time
| > | measure always involves something which has a movement) and the
| > | dilation factor can be choosen without considering it.
| > |
| > | Best regards,
| > | Lokman Kolukisa
| > |
|
.

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