Re: The relationship between meter, speed of light and c


"The Ghost In The Machine" <ewill@xxxxxxxxxxxxxxxxxxxxxxx> wrote in message
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In sci.physics.relativity, kenseto
<kenseto@xxxxxxxxxx>
wrote
on Sun, 18 Feb 2007 17:14:49 -0500
<45d8cea3$0$5806$4c368faf@xxxxxxxxxxxxxx>:

"The Ghost In The Machine" <ewill@xxxxxxxxxxxxxxxxxxxxxxx> wrote in
message
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In sci.physics.relativity, kenseto
<kenseto@xxxxxxxxxx>
wrote
on Sun, 18 Feb 2007 09:42:22 -0500
<45d86498$0$4881$4c368faf@xxxxxxxxxxxxxx>:


The point is that I'm predicting the wavelengths (W(v)) and frequencies
(R(v)) using ad hoc notation, given the velocities. That's what a
theory *does*.

If you prefer I can restructure the problem so that I can predict the
velocity given wavelength and/or frequency.

In IRT relative velocity is predicted as follows:
Mean relative velocity = v = Lambda(Faa-Fab)
OR
Instantaneous relative velocity = v =Lambda(f_aa - f_ab)

OK. Hopefully I've defined sufficiently well my ad hoc notation W() and
R() for you. From section 3 of
http://www.geocities.com/kn_seto/2007IRT.pdf
f_aa is defined as "the instantaneous frequency measurement of a
standard light source in A's frame as measured by A".
f_ab = "the instantaneous frequency measurement of a standard
light source in B's frame as measured by A".
lambda = "the universal wave length". [*]

The interesting thing is that section 1 defines

F_aa = "The frequency of a standard light source in A's frame as
measured by A". [+]
F_ab = "The frequency of a standard light source in B's frame as
measured by A; if F_ab is not constant the mean value is used."

The sole difference is the word "instantaneous"; they are otherwise
identical. Are they? This quirk to me is a little weird.
But let's see how far I get.

No that's not the only difference. The other difference is: If Fab is not
constant a mean value for Fab is used.

The predicted velocity v_irt = Lambda * (F_aa - F_ab).
F_aa is a given, as is Lambda. F(SR)_ab, from SR's
predictions, is F_aa * sqrt(1-v/c)/sqrt(1+v/c)
and of course includes the Doppler effect.

For doppler effect according to SR:
f(SR)_ab = f(SR)_aa*sqrt[(1-v/c)/(1+v/c)]
And this is converted to IRT equation as follows:
f_ab = f_aa*sqrt[(Fab)/(2 Faa-Fab)]

Unfortunately, the paper stipulates F_ab = 1/gamma,
which is an interesting difference.

You are an idiot.
Fab/Faa = 1/gamma

How one can directly
measure this is far from clear, since v
is not initially known.

Sigh....the point is in IRT we don't use v, c or gamma in IRT equations to
predict anything.
v is replaced lambda(Faa-Fab); c is replaced by Faa*lambda; gamma is
replaced by Faa/Fab; and 1/gamma is replaced by Fab/Faa.


Also, c = Lambda * F_aa, as stated just below.

Therefore

v_irt/c = (F_aa - F_ab) / F_aa
= 1 - sqrt(1-v^2/c^2)

I for one would hope that v_irt = v; clearly, however, this is not the
case. If one, for instance, substitutes v/c = 7/25 (to make the math
somewhat easy), one gets

v_irt/c = 1 - 24/25 = 1/25 != 7/25 = v

You are an idiot.....v_irt/c /= 1-24/25
There is no v_irt. There is v period.
The rest of your nonsense is snipped.

Ken Seto



.

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