Re: Do light have velocity dependent trajectories?

On 22 Feb, 14:25, "Dirk Van de moortel" <dirkvandemoor...@ThankS-NO-
SperM.hotmail.com> wrote:
<j...@xxxxxxxx> wrote in messagenews:1172147538.176219.170440@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

[snip]

Ok i am lazy is there a simple freeware graph program someware.

Sure:
http://www.google.com/search?q=free+simple+graphing+software+download

Dirk Vdm

Hello Dirk if i understand correct (plotted correct) the ligh pulse
will travel straight along the y-axis without deformation, regardless
of speed.

That makes me wonder a little, because after t1(earth/planet time 1
sec) the light beam have travelled 300 000 km relative earth.

But for the ship *distance* to pulsefront we would have to use
pythagoras theorem correct?

424 264 km

That would be the distance as measured from earth frame between ship
and pulsefront correct?

Assume velocity ship 0.9999 c we have a dilation factor of 1/70.7 sec
for inertial frame A ship.

1 sec earth frame =0.014144 ship frame

Should i conclude that the distance to pulsefront from within the
shipframe is 0.01414*424 264 ?

And that the distance to earth is 0,01414*300 000?

Is there other distances from within the ship frame to the pulsefront
and planet? "At moment t1"=clock 1 sec passed earth frame.

I know that length contraction occur in the ship frame does this apply
for space and things outside the ship?

Is there such a thing as distance contraction in SR or does it only
refer to the actual things belonging to the moving frame?

In my mind it would be natural to have the distance as a constant
between the frames 300 000/0,01414 and 424 264/0,01414 but that is of
course wrong according to SR.

Is distance really variant between frames in SR?
And what about the hypotenusa argument is that really invoked in SR?

Best regards Jonas Thörnvall

.

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