Re: SR theory is simplistic

bz

I am not for the moment adressing the experimental evidence. OK so
someone should have noticed
if there were c+v effects.

The moons in orbit - emitting photons system can be represented by a
turntable with two light bulbs
on the end, spinning rapidly.

To further simplify, the system can be represented by, at the widest
parts of the orbit , as by the observer, two light bulbs moving
tangentially, one towards the observer one away at say velocities
v_1 and v_2 where v1=-v2


My question is this: at any given time, measured in our frame, the
frame of the turntable,
the displacement between each emitter and the photon emitted is
different; photon 1 is closer to the
earth by s/v and so is photon 2. However the emitters are at different
distances from the earth.

What is the mechanism whereby a photon from two identical emitters can
be a different displacement
from the emitters (source) after a given time? Does this not violate
the principle of equivalance
when we are seeing two different sources emitting photons at different
velocities to themselves?

It is like saying since bullets travel at s metres ber second, if a
bullet is fired at the earth
by a moving gun, it will somehow arrive at the earth at s metres per
second because bullets allways travel at that speed.




G


On Mar 13, 11:07 pm, bz <bz+...@xxxxxxxxxxxxxxxxxxxx> wrote:
"G" <gehan_ameresek...@xxxxxxxxxxx> wrote innews:1173805075.661595.155420@xxxxxxxxxxxxxxxxxxxxxxxxxx:

bz

If I may revisit the previous post:

IF c'=c+v then moons moving away from us should show a different
'delay' than those moons moving toward the earth at the time of
occultation.

If I understand you correctly you are sayin that:

IF the suppostion that c' = c+v were true (if the photons leaving the moon
traveled at NOT c but c+v to earth THEN ---- [I do NOT believe for one
minute that the supposition is true, but will proceed as if it were]

The photon being emitted by the moon at the point in its obit when
travelling in the direction of the earth, this photon arrives at
earth at velocity c.

[if...then] It would arrive at earth at the velocity c+v, not c. Transit
would take less time by about 0.2 seconds out of ~43 minutes. Hardly
significant, you might think.

So does the photon emitted from the moon when
the moon is travelling directly away from the earth.

[if...then] it would arrive at earth at the velocity c-v, not c.
The trip would take longer for the 'slow' photons than for the 'fast'
photons. So they would arrrive about 0.2 seconds later than photons
traveling at c would arrive.

Now if you measure the tangential velocity of the moons at the points
in orbit when these earth bound photons are emitted, you will find a
difference between the velocity of the photon and
the tangential velocity of the moon at those points. The difference in
velocity between the
tangential velocity of the moon and the photons emitted at opposite
points of the orbit will not be the same.

Why?

In other words the photons leave the surface of the moons ( reflected
no doubt) at slower or faster
velocities so that they arrive at the earth at the same time. Why
should this be?

No. The slower photons would take longer to reach the earth than the
faster ones. The image of the moon in our telescope would be in a
different location. It would block light from distant stars (traveling at
c, rather than c+v) at a noticable different time than the visual image of
the moon should be seen as between us and that distant star.

Let us say the image of IO is .2 second ahead of the moment the star Xaaa
(pick a star's name) is occluded and for 0.2 seconds we can 'see the star
THRU IO'. Then later, as the star should emerge from behind IO, it doesn't
show up until 0.2 second later, and it is already separated from the
visual image by a noticable distance.

Do you think someone might notice?

Then, when IO is moving away from us, the effect is reversed, the 'slow
photons reflected from IO LAG behind photons traveling AT c from distant
stars.

The above assumes relative velocity between jupiter and earth are zero.

(Neglecting Earth's, Jupiters orbits etc)

...

Make observations when our velocities are maximum and there should be
larger discrepancies in the positions.

earlier I said:



Light from Jup takes an average of 43 minutes to reach us (depending on
where we and Jup are in our orbits, of course).

The light from the satelite should reach us about 0.216 seconds EARLY
when the satelite is coming toward earth and about 0.216 seconds LATE
when the satelite is going away from earth. This should produce a
noticable 'error' in orbital computations when we compare the orbit
with data space craft orbiting jupiter, we should notice.

Jupiter orbits the sun at 13.0697 km/s. Earth orbits the sun at 29.7859
km/s.
That means that at times jupiter and earth are closing at close to
42.86 km/s and at times we are going away from each other at that
speed. This would result in +/- 0.372 seconds variation or 0.745
seconds. Now add THOSE to the orbital velocity of that moon and you
have 1.178 second discrepancy in photon arrival times.

--
bz

please pardon my infinite ignorance, the set-of-things-I-do-not-know is an
infinite set.

bz+...@xxxxxxxxxxxxxxxxxxxx remove ch100-5 to avoid spam trap


.

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