Re: Our greatest problem!
- From: "PD" <TheDraperFamily@xxxxxxxxx>
- Date: 10 Apr 2007 08:39:40 -0700
On Apr 10, 8:49 am, "kenseto" <kens...@xxxxxxxxxx> wrote:
On Apr 9, 10:59 am, The Ghost In The Machine
<e...@xxxxxxxxxxxxxxxxxxxxxxx> wrote:
In sci.physics.relativity, kenseto
<kens...@xxxxxxxxxx>
wrote
on 9 Apr 2007 06:21:14 -0700
<1176124874.519427.83...@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>:
On Apr 7, 4:36 pm, karandash2...@xxxxxxxxx wrote:
On Apr 7, 11:22 am, "kenseto" <kens...@xxxxxxxxxx> wrote:
[snippage]
No my proposal for the modified MMX is: the plane of the arms is
oriented vertically. A fringe shift should be observed when the arms
are rotated. The reason for the predicted shift is that different
heights of the arms (when they are rotated) will yield different
frequencies and thus the predicted fringe shift.
Umm, no. Different frequency does NOT result into a fringe shift.
As usual, your math betrays you.- Hide quoted text -
- Show quoted text -
So what does result into a fringe shift.....wavelength or speed of
incoming light? You keep on saying that my math betrays me but I
didn't give any math for the proposed modified MMX.
I show eqautions 15 and 16 for my proposed experiment.
Someone's going to have to explain to me precisely how a
speed increase or decrease without a change in wavelength
will result in a fringe shift when one uses a diffraction grating.
:-)
Hey idiot constant wavelength (or universal wavelength) means that the
detected frequency shift of the incoming is caused by a different
speed of the incoming light which, in turn, means the detection of
absolute motion which, in turn, causes fringe shift.
Unfortunately no. If there is no wavelength change, then there is no
change in deflection in a diffraction grating, period, by the way that
diffraction gratings work.
PD
.
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