Re: Are There Unresolver Foundational Issues With GR
- From: Koobee Wublee <koobee.wublee@xxxxxxxxx>
- Date: 27 Apr 2007 17:52:13 -0700
On Apr 27, 4:37 pm, JanPB <film...@xxxxxxxxx> wrote:
On Apr 27, 4:02 pm, Koobee Wublee <koobee.wub...@xxxxxxxxx> wrote:
A better question is to ask what physically DESCRIBES a geometry since
nothing can change or determine the geometry. If you ask that
question, I will answer.
It's not just a DESCRIPTION - if that was the case, nobody would
bother you :-)
When talking about an invariant object or a feature, we can only
describe. We cannot change it.
The problem with your claims is that you insist on an
_actual physical difference_ between certain two expressions for ds^2
differing only by a coordinate change - you said in one such case, for
example, that one of the ds^2 exhibited a black hole while the other
one didn't.
No, I did not say that. I said since the field equations are only
valid for a set of coordinate system that we initially have chosen,
any solutions found must be conformed to this coordinate system and
nothing else. If there are two solutions, then each metric must
represent a different geometry since both metrics employ the same
coordinate system. With the field equations able to predict the
existence of so many independent metrics at the same time, the field
equations must be wrong, silly, and absurd.
The analogy is like solving the following quadratic equation.
x^2 - 4 x + 3 = 0
The solutions are
** x = 1
** x = 3
To say (x = 1 = 3) is wrong, silly, and absurd. To insist on (x = 1 =
3) is barbaric, irrespnosible and sinister.
Bottom line:
I'd like to know how two functions assigning the same lengths and
angles to the same vectors can STILL be considered as different
solutions to Einstein's equation.
They can't, but they do exist. Thus, the field equations are just
wrong, silly, and absurd.
What distinguishes them, physically?
The metric with identical coordinate system.
.
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