Re: Einstein's Photoelectric = Newton Mechanics??
- From: "guskz@xxxxxxxxxxx" <guskz@xxxxxxxxxxx>
- Date: 30 Apr 2007 08:24:22 -0700
On Apr 30, 8:05 am, bz <bz+...@xxxxxxxxxxxxxxxxxxxx> wrote:
"g...@xxxxxxxxxxx" <g...@xxxxxxxxxxx> wrote innews:1177905635.648142.215280@xxxxxxxxxxxxxxxxxxxxxxxxxxx:
If we must obey Planck's constant "h" for ONE unit of light then it
seems obvious that Einstein's Photoelectric effect obeys Newtonian
Mechanics??
Einstein's two photoelectric effects are:
1. More intense the light, the MORE electrons move at the same
velocity
2. Faster the frequency of light, the SAME electrons move at a FASTER
veloctity.
------------------------------------------
#1 is explained by adhering to Planck's constant, therefore a higher
intensity of light means a higher quanta value per square unit of
space therefore means more photons travelling simultaneously. (More
photons move more electrons???)
#2 is explained also due to Planck's quanta, therefore the same
intensity (same number of photons) hit the same number of electrons
but a higher repetitive(frequency) rate thus the same number of
electrons will obviously move faster????
_________________________
Science says Einstein's photoelectric effect explains particle-wave
duality, I say it explains Newton's Mechanics Law.
Newton's laws do not include 'quantitization'. It was not invented until
MUCH later.
Of course, but the quanta simply defines the "size" of the particle.
Newton Mechanics believed everything to be particle.
Under Newtons laws, a weaker beam of light would consist of particles or
waves that move with less amplitude or move slower.
That's a tricky concept because wave functions are exactly like waves
of voltage
versus waves of current, yet both are manifested by the same electron
in motion.
Your concept above is more a wave of voltage (wave of force = EMF)
where as if you use
a wave of current (wave of particles ...for the Photon beam) then it
would obey Newtonian Mechanics.
As the beam is attenuated, the electrons would get weaker.Your "weaker" is a ambiguous...
1. did you mean a weaker number of electrons disturbed into motion
2. did you mean a weaker force excerted upon the electrons
3. did you mean a weaker velocity per electron
4. did you mean a specific combination of the 3 above
-----------------------
By your short definition above is what happens during the
Photoelectric Effect...
AA) either a weaker number of electrons
BB) or a weaker velocity per electron
And both AA & BB obey Newton's conservation of momentum thus
Newtoninan Mechanics
A larger intensity = a larger number of billiard balls hitting more
electrons (conservation of momentum)
A larger frequency = a constant number of billard balls hitting the
same electrons in REPETITIVE SUCCESSION will produce a higher velocity
per electron (conservation of momentum)
---------------------------
But I understand that your higher intensity per particle in motion
reflects a higher force or velocity of a SINGLE particle (or constant
number of particles) and not higher current and by that definition
Newtonina Mechanics would fail.
We must define what is higher amplitude (voltage/force/velocity/EMF)
and what is higher intensity(current/# of coulombs/# of particles) in
terms of a Photon beam....and how these are measured.
Can they like for electrons measure a higher amplitude? for a light
wave as well as a higher intensity (hotter beam)?
Where's my Nobel ???
No bell for you.
Correct it will awarded in 150 years to someone else using the same
analogy, but on a more complex and different phenomena.
--
bz
please pardon my infinite ignorance, the set-of-things-I-do-not-know is an
infinite set.
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