Re: Bohr's Atom still number one
- From: "guskz@xxxxxxxxxxx" <guskz@xxxxxxxxxxx>
- Date: 1 May 2007 23:00:10 -0700
On May 1, 5:46 am, bz <bz+...@xxxxxxxxxxxxxxxxxxxx> wrote:
"g...@xxxxxxxxxxx" <g...@xxxxxxxxxxx> wrote innews:1177995332.605199.251900@xxxxxxxxxxxxxxxxxxxxxxxxxxxx:
(b) the s-orbital is spherical and the Bohr orbit is not
Bohr's orbit isn't circular? then what is it squarical?
Circular is not spherical.
A circular orbit has one kind of symetry.
A spherical orbit had a completely different kind of symetry.
An atom with a circular orbit will only bond with atoms that lie on the
plane of the orbit.
A atom with a spherical orbit will bond with atoms in any direction.
The chemistry of atoms that have 's' orbitals containing their bonding
electron clearly shows spherical symetry, not circular.
Bohr's orbitals ALL lie in the same plane.
Bohr's model is disproved by the bonding of molecules.
--
bz
please pardon my infinite ignorance, the set-of-things-I-do-not-know is an
infinite set.
bz+...@xxxxxxxxxxxxxxxxxxxx remove ch100-5 to avoid spam trap
There is an obediance (non-random and non cloudy/fuzzy) of perfect
INTEGER symmetry that is "demanded" in the GEOMETRY of the atom for
the Table of Elements to obey the quantum principle and for the
electron's nescessity to shed or gain light at specific intervals in
this geometry.
It is a no dice game.
.
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