Re: Bohr's Atom still number one

On May 4, 7:55 am, bz <bz+...@xxxxxxxxxxxxxxxxxxxx> wrote:
"g...@xxxxxxxxxxx" <g...@xxxxxxxxxxx> wrote innews:1178265060.348289.136990@xxxxxxxxxxxxxxxxxxxxxxxxxxx:





On May 2, 7:55 pm, bz <bz+...@xxxxxxxxxxxxxxxxxxxx> wrote:
"g...@xxxxxxxxxxx" <g...@xxxxxxxxxxx> wrote
innews:1178142990.583307.260730@xxxxxxxxxxxxxxxxxxxxxxxxxxxx:

Meaning as the electron approaches or moves away from the nucleus a
photon is shed or absorbed.

Incorrect.

The position is not known well enough to be able to say that it moves
toward or away from the nucleus at the time a photon is absorbed or
emitted. The fact is that that the position of the electron is
'uncertain'.

All we know for sure is that the energy level of the electron( and the
quantum numbers associated with the electron) change. The probability
distribution changes. The AVERAGE distance from the nucleus changes.
But the electron, itself, at the moment of emission, may very well NOT
move at all.

Since they can isolate electrons (slit experiment) then likewise by
now they should have figured out when the electron absorbs and when it
emits light.

SHould have and have are different.

I believe it only occurs during acceleration and deceleration and
nothing happens at constant velocities.

Your faith is touching. If electrons were like planets, they would be
constantly undergoing acceleration as they 'fall around the nucleus'. That
is why the Bohr model is so boring.


A wave is constantly varying (thus accelerating and decelerating).

All we know for sure is that changes in energy state SOMETIMES are
accompanied by emission of photons and that absorption of a photon results
in changes in the energy level(s).



As well they total energy (including photons) of all reactions as
elements turn into ions and vice-versa

Please translate into english.


When you have a chemical reaction....don't they know the total energy
of before and after (energy = heat from reaction = photons)

Don't know my chemistry....say 2H+ + O- + E = H2O +....


They should know the total energy before and after of chemical
reactions (therefore the total photons produced or absorbed as well)?


We do know that in molecules, the positions of the nuclii do NOT change
immediately. See the Frank-Condon Principle.

And if I knock off planet Earth, the Sun itself will not be affected
all that much.

'do NOT change immediately' does NOT mean 'will not be affected all that
much'. There are effects. The energy levels are immediately effected but
not the positions.


The sun will also be affected and there will be a similar delay
before this occurs.
--
bz

please pardon my infinite ignorance, the set-of-things-I-do-not-know is an
infinite set.

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