Re: Bohr's Atom still number one

On May 8, 11:45 pm, "g...@xxxxxxxxxxx" <g...@xxxxxxxxxxx> wrote:
On May 7, 6:07 pm, PD <TheDraperFam...@xxxxxxxxx> wrote:





On May 7, 2:10 pm, "g...@xxxxxxxxxxx" <g...@xxxxxxxxxxx> wrote:

The point being you gave an incorrect comparison....the cyclotron
accelerates the electron(= electron has higher and higher velocity as
it travels in the cyclotron/magnetron) but the electron does not
accelerate(= constant velocity) around a nucleus if it is traveling in
a perfect circle.

That is incorrect. Electrons will radiate while *coasting* around an
accelerator ring at constant velocity.

But the significant difference is that electrons do not go in a ring
around the nucleus. They don't go in a circle around the nucleus at
all. This is precisely the problem with the Bohr model. If they did go
around in a circle, they would have to radiate.

PD

The cyclotron's field(s) are in the linear path of the electron
instead of a constant nucleur centre.

That's not so. If it were true, the electron would proceed in a
straight line rather than bending in a circle.


Does anyone dispute that electrons shed photons to get closer to a
nucleus?

Actually, they shed photons to get to a lower energy state. That is
closer to the nucleus in Bohr's model, but not necessarily in reality.
See a freshman chemistry text.

Does anyone dispute only "x" amount of electrons can be found at any
one time around a nucleus?

The three above are the answer.- Hide quoted text -

- Show quoted text -


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