Re: The velocity of light going pass a moving train.

On Jun 17, 12:49 am, "Jeckyl" <n...@xxxxxxxxxxx> wrote:
"Dono" <s...@xxxxxxxxxxx> wrote in message

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On Jun 16, 8:24 am, G <gehan_ameresek...@xxxxxxxxxxx> wrote:
On 16 Jun, 18:58, Dono <s...@xxxxxxxxxxx> wrote:

On Jun 16, 3:06 am, "Jeckyl" <n...@xxxxxxxxxxx> wrote:

"Dono" <s...@xxxxxxxxxxx> wrote in message

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On Jun 15, 9:42 am, "Jeckyl" <n...@xxxxxxxxxxx> wrote:
"Dono" <s...@xxxxxxxxxxx> wrote in message

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On Jun 15, 9:18 am, "Jeckyl" <n...@xxxxxxxxxxx> wrote:
"Dono" <s...@xxxxxxxxxxx> wrote in message

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Actually , you got it wrong, Harry.
And it is such a simple problem. "G" is indeed correct, how
would the
light go diagonally in the track frame? Moreover, why would
the light
ray get inclined forward in the direction of the train motion?

Its very simple .. it HAS to be inclined forward in the track
frame in
order
to be vertical in the train frame.

Well, you may be in for a surprise, it is inclined backwards,
not
forwards in the track frame. Harry here will be more than happy
to
explain that to you (once he understands my explanation to him)

Nonsense.

1. Upward light trip as viewed from the track

Train Motion --->
^
^Center of Ceiling Mirror

^ Light Strike on Ceiling Mirror (off-center)
^
^
^
^Light Emittor on the Train Floor

2. Downward light trip as viewed from the track

Train Motion --->

^ Light Strike on Ceiling Mirror (off-center)
* ^
* ^
* ^
*LightStrike on the Train Floo

Have fun! Hope you learned something new.

No .. I already knew you had no idea what you're talking about.

Its perfectly simple .. if the light is travelling vertically in the
train,
then from the frame of the track it is inclined in the direction of
the
travel of the train .. it has to be. There is no other possibility-
Hide quoted text -

- Show quoted text -

"It has to be" has no room in science.Bye.

Light emitted in my frame of reference is glued to my frame of
reference in terms of velocity
Just because the source of light is on the train and "inside" the
train does it mean it is in a different frame
of reference? What if it was an open train? what if it was a light
source moving along the tracks ( commonly called an UFO)
My frame ( frame of the tracks) behaves as if it was filled with
stationary ether ( relative to me and the tracks)

What if it was a laser pointer travelling over the tracks ? what if it
was horizontal? Would we find the laser travelling a greater
distance because it is moving? Will the ray of light emitted from the
laser travel a greater distance ?

Is it starting to unravel yet, folks?

Unravel what?
If the laser were set horizontally the calculations are even simpler.
Assume that the length of the train car is 2*L and the train car speed
is v

1. Forward going beam

c*t_forward=L+v*t_forward

t_forward=L/(c-v)

2. Backward going beam:

c*t_backward+v*t_backward=L

t_backward=L/(c+v)

I assume you are talking completely about the FoR of the track.. In which
case the L here would not be the rest length of the train, but the
contracted length as per Lorentz transforms.



Did I say that L was the rest length of the train?

.

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