Re: The velocity of light going pass a moving train.



On Jun 19, 7:05 am, "Jeckyl" <n...@xxxxxxxxxxx> wrote:
"Dono" <s...@xxxxxxxxxxx> wrote in message

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On Jun 18, 4:36 pm, "Jeckyl" <n...@xxxxxxxxxxx> wrote:
"Dono" <s...@xxxxxxxxxxx> wrote in message

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You didn't really do a very good job of defining it at all. You
also
didn't
say in which direction the laser was pointing .. we had to assume
you
meant
in the x axis (direction of travel of the train).
You need to learn how to read.
I can .. you need to learn how to write .. you said something that was
COMPLETELY wrong,
No, idiot, you are still unble to understand it, too complicated for
your brain.
I understood what you wrote .. you were simply incomplete and unclear ..
and
wrong
If you understood as you claim you will not have any trouble
explaining (with math) the following :
1. Why can light be aberrated towards the rear of the car in
Einstein's experimen.

Which experiement? We were talking about a light beam that was pointing
vertically in the frame of the train .. and you said it would be pointing
backward in the opposite direction to the way the train is moving from the
frame of the track .. that is clearly nonsense.


....you still don't get it, after all the explanations. Man, you are
dumb.


2. What is the aberration angle in the problem at point 1?

What problem?


Classical crank answer. The problem that started it all, the beam
points vertically in the car frame, what direction does it point in
the track frame, dumbo?


3. How do the equations at point 1 change if the "light clock" is
turned 90 degrees ( horizontally)

What light clock?


A beam of light bouncing between two mirrors is called a "light
clock", dumbo. Go get some education, you are way, way too ignorant.
And it shows.




Next time, before you shoot your mouth, ask questions, I will
explain
to you.
Next time .. keep your mouth shut to avoid embarrassing yourself.
You are still an idiot after all the mathematical explanations. Too
bad.
You wrote a couple of trig formulas .. that doesn't make you right.
It does, since the formulas and the explanation are correct.

No .. its not. You're misapplying it. Or there is a massive failure in how
you're explaining the thoguht experiement and the result you are predicting.


Classical crackpot, you don't understand that (though it is simple
fare in physics 101) , therefore it must be wrong.


If a
beam of light is vertical in the frame of reference in the train ,it does
NOT seen going backwards (in the opposite direction to the train) from
the
FoR of the track

At least you are persistent in terms of repeating the same idiocy, the
main trademark of crackpots.

You're the crackpot here .. have you even thought about this problem at all?

Of ourse, it is simple fare in beginner classes. Try writing some math
instead of shooting your stooopid mouth.



Of course, it is seen backwards from the
FoR of the track:

You're a complete fool .. A light shining vertically upward in the train
would be seen shining diagonally forward in the direction of travel from the
FoR of the track.

Well, I guess that your stooopidity must be incurable by now. Google
"Einstein light aberration formula".



It has to be,

"It has to be", classical crackpot fare. Because it "feels right" to
you, eh?


if the track saw it going backward, then
the beam would be out the back door of the train before it got anywhere near
the roof of the train.


Ummm, mo. Try calculating instead of shooting your mouth.
- try writing the math,
- try thinking about how "separation speed" works when the
trajectories of the two elements involved (light beam and the mirror
attached the the roof)

What mirror?

Idiot, in my first post to you I showed you the light bouncing between
the mirror placed on the train floor and the train ceiling. That post
showed you graphically (since you don't know math) how light is
aberrated.

are perpendicular to each other

Have you actually tried thinking about this problem? From the ridiculous
answer you give .. that the light would be angled backward in the FoR of the
track, you obviously have not .. you've applied a formula without thinking
when and how it should be applied.


Classical crackpot again. Yes, I thought about it. I tried to educate
you but you are way too stooopid to get it.


Both approaches should give you the same result, backwards aberration.
I.e. if you stop being a crank and you learn some physics.

Talk about the pot calling the kettle black. Try using a little common
sense.

"Common sense", you have all the crackpot clichees. Try learning some
physics, enroll in a class someplace, your crass ignorance combined
with your "common sense" is blocking your understanding.


.



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