Re: The velocity of light going pass a moving train.

<paparios@xxxxxxxxx> wrote in message
news:1182304569.537960.215000@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
On 19 jun, 21:42, Dono <s...@xxxxxxxxxxx> wrote:
On Jun 19, 6:11 pm, "papar...@xxxxxxxxx" <papar...@xxxxxxxxx> wrote:
See last part ofhttp://en.wikipedia.org/wiki/Relativistic_aberration

Miguel Rios

Yes, I kept trying to get dr.Jeckyll to understand it ......I already
showed him the formula, to no avail (at least, so far).

But the important part is:

"In these models, rays of light emitted by an object are seen by a
bystander with a different state of motion to be tilted more towards
the direction of the object's motion."

Indeed.. note that that is true of aberration in general .. with
relativistic aberration, the amount of 'tilt' is more pronounced. So if the
train were travelling at very close to c, then instead of the classical
prediction of ~45deg aberration, relativity says it will be ~0 degrees.

The main point is the direction of the aberration (ie if the source was
fixed and upward vertically within the train, then from the track FoR the
light would be include upward and tilted in the direction of the train's
motion, but tilted over more than classical physics would predict.




.

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