Re: The velocity of light going pass a moving train.

On 20 jun, 18:29, Dono <s...@xxxxxxxxxxx> wrote:
On Jun 19, 11:05 pm, "Jeckyl" <n...@xxxxxxxxxxx> wrote:
"Dono" <s...@xxxxxxxxxxx> wrote in message

news:1182303768.824683.175520@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

Yes, I kept trying to get dr.Jeckyll to understand it ......I already
showed him the formula, to no avail (at least, so far).
You were simply misunderstanding the problem and so coming up with the
wrong
solution.

No, idiot.

Yes, fuckface

You simply don't understand aberration,

That's a joke coming from you

that is all.
If you stopped talking and you started using math you would
understand.

If you started thinking about HOW you are using the math, you'd see you have
the wrong sign for the velocity.

But since you avoid using math like the plague, you keep
repeating the same errors.

You are the one with the wrong answer, buddy.

It helps when you are actually talking about the same problem as
everyone else (G, Harry, myself). As I said .. you were using the
right
formulas but misapplying it (as far as the problem the rest of us were
talking about).

Again, no, idiot.

Again, yes, fuckface

The description of the problem in math terms is not
as ambigous as you keep making it to be.

Yet you get it wrong

Here it is, one more time, mr. Jackasss:
-In the traincar frame theta_car=pi/2
-In the track frame
cos(theta_track)=(cos(theta_car)-v/c)/(1-v/c*cos(theta_car))

Your v has the wrong sign when you apply it. You need ot understand what
the terms mean before you go plugging values in.

So, can you calculate cos(theta_track)? I asked you 5 times, why are
you so shy about using a little math?

I'm not shy about it:
I know the math
I know how it works
I know how to apply it.
You only seem to know the first of those, which makes you get the wrong
answer. I even made a post earlier where I showed the answers for both
classic and relativistic aberration (with exaplanations of why it works that
way).

Since you don't get the math

I do .. but you got it wrong

and you didn't get the "separation speed" explanation,

You don't seem to undertand ANY explanation .. I've tried .. but you're just
too obsessed with the "math" to see how to apply it

I will give you a third explanation:

This should be amusing

since in relativity
all frames are equivalent, instead of having the train moving Left to
Right with respect to the tracks, imagine that the tracks move Right
to Left while the light bounces vertically in the car frame.

Yeup .. all fine so far .. its exactly the same scenario .. only the
previous explanation was a simpler way of expressing it.

How is
the light inclined in the track frame?

Exactly the same .. someone in the track frame will see the light travelling
up and to the right (in the direction of travel of the train) when it goes
up and down and to the right when it bounces back down to the floor. It has
to .. as the train will be going way off into the distance in the right hand
direction, and the light will still be in the train .. it HAS to be going in
the same direction. Just try thinking about it for a moment .. ok?

If you still don't get it,

I understand aberration (classic and relativistic) apparently much better
than you already

look at these pictures:
http://www.fourmilab.ch/cship/aberration.html

Yeup . they all agree exactly with what I said .. maybe you should look at
it again .. and keep looking until you can see how wrong you are.



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