Re: The velocity of light going pass a moving train.

"Dono" <sa_ge@xxxxxxxxxxx> wrote in message
news:1182407608.284637.102240@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
On Jun 20, 10:26 pm, "Jeckyl" <n...@xxxxxxxxxxx> wrote:
You are using the correct formula .. but applying it incorrectly. BTW:
Do
you even understand relativistic aberration works, and why you get a
great
difference in angle when you take relativity into accout.

Yes, I do idiot. Now check with the guy who was the first to derive
the formula:
http://www.fourmilab.ch/etexts/einstein/specrel/www/


i.e. it makes an angle greater than 90 degrees with the semipositive
x-axis.
Try understanding the relativistic aberration formula, would you?

How about you try it .. you seem to think the light goes the wrong way

Check with Einstein, you ignorant twit:
http://www.fourmilab.ch/etexts/einstein/specrel/www/

You are such an obnoxious little prick

When the light is moving vertically upward in the train, and the train is
moving left to right in the track frame, then from the track frame, the
light will be seen moving left-to-right as it moves upwards.

ie from FoR of the track

+
+
+
+ angle 63deg
+-------------------->> motion of the train

if ==== represents the floor and ceiling of the train , and + a photon in
the light. Then when the light leaves the floor, from the track we see

====




+
====

when it reaches the ceiling we see from the track
====
+
/
/
/
/
====

See that the light inclines in the direction of the motion of the train?

In particular, if the train is moving at 0.5c, then the angle the that track
observer would see the light making with the x-axis is atan(2) ~= 63deg.


.

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