Re: The velocity of light going pass a moving train.

On Jun 21, 11:00 am, Dono <s...@xxxxxxxxxxx> wrote:
[...]

Incorrect. In the track frame, while the light travelled from the
floor to the ceiling, the train moved from LEFT to RIGHT.
In mathematical terms:

1. In the train frame the light makes an angle pi/2 with the
semipositive x axis, so cos(theta_car)=0

2. The track frame, according to the relativistic aberration formula

cos(theta_track)=(cos(theta_car)-v/c)/(1-v/c*cos(theta_car))

so

cos(theta_track)=-v/c

meaning that , in the track frame, the light wave vector k, makes an
andgle LARGER than pi/2 with the semipositive x-axis

In other words, contrary to what you are saying, the light beam in
inclined towards the REAR of the car as viewed from the frame of the
tracks.
This makes perfect sense, since, as pointed out earlier, the car has
moved from the LEFT to the RIGHT while the light travelled from the
floor to the ceiling.

Now, the above system would not allow for dtection of absolute motion
because, inside the closed car the light moves perfectly vertically
regardless of the car speed v. So, an observer closed inside the car
would not be able to detect any "absolute motion"

QED has some legitimacy in its claim of "the most sucessful
theory ever". Try to get a copy of:
http://en.wikipedia.org/wiki/QED_(book)
....and learn the correct way to model light as a particle.
Then you'll have no problem with bz's solution.

Sue...






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