Re: The velocity of light going pass a moving train.

Dono <sa_ge@xxxxxxxxxxx> wrote in news:1182450172.908373.143140
@a26g2000pre.googlegroups.com:

right, for the train's frame.

cos(pi) = -1.

The beam misses the mirror, in which direction?
cos(0) = 1.

The beam misses the mirror, in which direction?


In the track frame the beam hits the mirror a little behind the
center, in the direction opposite to the train movement.



No. I am asking you to interpret the cos(pi) = -1 and cos(0) = 1 figures
for me. Assume that there is a laser that can be configured to aim in the
zero direction and the pi direction. Just in the train frame, which
directions are the 0 and the pi and what toes the -1 and 1 mean, exactly,
to you?

You may draw a diagram, if you like.

I am trying to find out how you have your protractor oriented and how you
are defining your angle theta.






--
bz

please pardon my infinite ignorance, the set-of-things-I-do-not-know is an
infinite set.

bz+spr@xxxxxxxxxxxxxxxxxxxx remove ch100-5 to avoid spam trap
.

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