Re: The velocity of light going pass a moving train.

Dono <sa_ge@xxxxxxxxxxx> wrote in news:1182450172.908373.143140
@a26g2000pre.googlegroups.com:

Correct, the beam hits the center for the train observer but does not
for the track observer. The reason is that the mirror has moved to the
right while the beam travelled from the floor to the ceiling.

You are ignoring the fact that the trackside observer MUST observe the beam
hitting the mirror in the exact same place that the observer on the train
sees it hit.

Take a bead on a rod, going from floor to ceiling. Bead moving up and down
rod at constant velocity of 1 ft per second. Train moving at 1 ft per
second.
rod ten feet long.

Bead travels 10 feet horizontally and 10 feet vertically in 10 seconds,
from trackside observers viewpoint.
Bead travels 10 feet vertically in 10 seconds from train observer's view
point.

Bead can not leave rod. Bead's velocity is different, as measured by
observer in train and trackside observer. Angle of path is different for
different observers. Bead still does not leave rod.

Same for light clock one light nano second tall.

Light can not leave its vertical path, no matter if train is stationary or
moving at .999996 c.

What varies is the TIME it takes to travel the path, and the length of the
path in the trackside observer's iFoR. The light still hits center of top
mirror. Different observers see the light move different distances. Their
clocks show different time for the transit. But all measure the velocity of
the light at c, using their own clocks, rulers, etc.







--
bz

please pardon my infinite ignorance, the set-of-things-I-do-not-know is an
infinite set.

bz+spr@xxxxxxxxxxxxxxxxxxxx remove ch100-5 to avoid spam trap
.

Relevant Pages

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