Re: How do we measure the energy of this light wave?

On Jun 26, 6:41 am, "g...@xxxxxxxxxxx" <g...@xxxxxxxxxxx> wrote:
On Jun 26, 4:43 am, "Sue..." <suzysewns...@xxxxxxxxxxxx> wrote:





On Jun 26, 4:57 am, "g...@xxxxxxxxxxx" <g...@xxxxxxxxxxx> wrote:

Since energy is never lost (a dead battery emitted energy away before
it became dead).

Two polarized same mono-frequency light waves(or lasers) with a
TRILLION volts of energy are exactly 90 degrees out of phase and along
the same trajectory thus due to superposition will they be invisible?

Will they be harmless?

Will we be able to notice the difference between them and an empty
space?

If you put an observer in the space, it won't be empty.

<< Figure 3: The wave impedance measures
the relative strength of electric and magnetic
fields. It is a function of source [or absorber] structure. >>http://www.sm.luth.se/~urban/master/Theory/3.html
Formerly:http://www.conformity.com/0102reflections.html

<< Are you saying the em fields don't cancel-out? >>

Yes... That is why automobile headlamps do not
have to obey traffic signals.

Sue...




http://en.wikipedia.org/wiki/Wave_impedancehttp://en.wikipedia.org/wi...

You may however be the unique observer that
could participate in such an experiment given
the quality of vacuum between your ears.

With aluminum ear muffs you might discover
hitherto unheard of phenomena. :o)

http://www.google.com/search?hl=en&q=%22shut+up+and+calculate%22&btnG...

Sue...- Hide quoted text -

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