Re: E=F/q=vB Magnetic Force does not work on the charge



On Jul 13, 6:28 am, Eric Gisse <jowr...@xxxxxxxxx> wrote:
On Jul 12, 11:54 pm, "gu...@xxxxxxxxxxx" <gu...@xxxxxxxxxxx> wrote:





On Jul 12, 6:11 pm, Eric Gisse <jowr...@xxxxxxxxx> wrote:

On Jul 12, 2:03 pm, "gu...@xxxxxxxxxxx" <gu...@xxxxxxxxxxx> wrote:

On Jul 12, 4:48 pm, Randy Poe <poespam-t...@xxxxxxxxx> wrote:

On Jul 12, 4:39 pm, "g...@xxxxxxxxxxx" <g...@xxxxxxxxxxx> wrote:

Model: A wire moving perpendicularly through a N&S magnetic field

Which way is the current flowing in this wire? Which way
is the wire moving?

Quote:

Who are you quoting?

"It is ****ERRONEOUS**** to think that the magnetic force does
work on the charges to produce an EMF. We recall that the magnetic
force is PERPENDICULAR to the velocity and hence to the displacement
of the charge deltaW= F deltaS Cos(angle) where deltaS = displacement
and in this case angle = 90 degrees therefore NO WORK IS DONE BY THE
*****MAGNETIC FORCE********."

If one cannot figure out that the reverse is also true and that a
magnetic force also does not affect a perpendicularly moving charge,
absolutely no interaction occurs.

There is a simple relationship between velocity, magnetic
field, and force experienced by a charge. It is:

F = qv x B

That says that, contrary to your statement,

McGrawHill "Elements of Physics" book.

Open up a real electrodynamics text.

No but really, what a childish reply, if now you are saying that the
BOOK is incorrect. Then you need to start school again.

Open up a real electrodynamics text, so you don't sound like a moron


Well son, append what information you have = none, zero, zilch that
"you" think is missing and needed that is not quoted from the book.

Since you are so insistant, otherwise stop complaining.



.



Relevant Pages

  • Re: E=F/q=vB Magnetic Force does not work on the charge
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  • Re: E=F/q=vB Magnetic Force does not work on the charge
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