Re: F=qvxB: PROOF that Force on charge or wire is the same
- From: "guskz@xxxxxxxxxxx" <guskz@xxxxxxxxxxx>
- Date: Fri, 13 Jul 2007 12:09:59 -0700
On Jul 13, 2:58 pm, "gu...@xxxxxxxxxxx" <gu...@xxxxxxxxxxx> wrote:
Example:L = length of wire that lies in between the two N&S magnets
Water flows at 2 gallons/sec.
Gallon say contains 1 million water molecules
The area x length that contains the water is 1000m^2 x 100^m.
Can you figure out how many water molecules there is, and what is
their average velocity in m/sec.....Answer is yes.
**********LIKEWISE**************
Model: Current in a wire moving in between two N &S magnets
I = amperes = coulombs/sec = n_I q/sec (n_I is the number of charges)
A = area of wire
L = length of wire
F = ILB = n_I AL qv B
Since the number of charges in L is n_I *A* L = "n" therefore
F= nqv B where "n" is the total number of charges affected by the
magnetic field B.
-----------------------------------------------------
More precisely F= nqv B sin(angle) is the EXACT same as the Force
applied on a single charge where n = 1 ( F_singlecharge = qv B
sin(angle) )
In fact both the wire and the single charge also deflect in the same
direction as pertaining to the right hand rule.
CONCLUSION: THERE IS NO DIFFERENCE BETWEEN THE ****FORCE**** OF TWO
N&S MAGNETS ON A SINGLE CHARGE OR ON THE CURRENT (MULTIPLE MOVING
CHARGES) IN A WIRE.
***********************************
The above is important because in the physics book that specifies the
force is a result between the ****magnetic field of the current*****
versus the magnetic field of the N&S magnets thus LIKEWISE for a
single charge.
McGrawHill physics book quote: "...on one side of the wire the
magnetic field ****DUE TO THE CURRENT**** reinforces the field ALREADY
present (meaning the already present field of the N&S magnets) while
on the "other side" of the wire the two fields are OPPOSITE in
direction."
...."the force on the wire is directed from the stronger field TOWARD
the weaker one, or from the side on which the two fields reinforce to
the side on which the two fields oppose"
And the Force for the current in that wire = nqv x B thus nqv DOES
NOT MEAN the circular magnetic field doesn't interact with the N&S
magnet's magnetic field.
(F= g x m and not F= g x Gm/r^2 likewise for F = B x nqv)
.
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- From: guskz@xxxxxxxxxxx
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