Re: Twin paradox revisited ll

"Sue..." <suzysewnshow@xxxxxxxxxxxx> wrote in
news:1185211838.607102.222450@xxxxxxxxxxxxxxxxxxxxxxxxxxxx:

On Jul 23, 10:38 am, bz <bz+...@xxxxxxxxxxxxxxxxxxxx> wrote:
"Sue..." <suzysewns...@xxxxxxxxxxxx> wrote
innews:1185192380.289601.223070@xxxxxxxxxxxxxxxxxxxxxxxxxxx:







On Jul 23, 7:21 am, bz <bz+na...@xxxxxxxxxxxxxxxxxxxx> wrote:
"Sue..." <suzysewns...@xxxxxxxxxxxx> wrote
innews:1185165923.734777.4890@
57g2000hsv.googlegroups.com:

....

There is no sign that they observed anomalous muon half lifetimes.

Would you like to try again to cite something that actually supports
what you have been saying?

Sorry... muons just ain't your daddy's railroad watch.
Nor are they they like a hair follicle.
Nor are they produced only in the upper atmosphere.
That is my point. The experiment does not
support "anomalous ageing of a twin".

It supports normal ageing of a muon.

Normal ageing of a stationary muon, regardless of what they are
'coupled to'.

Whereas muons kept moving near c age much slower, be they in the upper
atmosphere or in a particle accelerator.

I do NOT see how that supports your position, which would seem to
require those in strong magnetic fields (or blocks of iron) to live
longer, even if they were stationary.







Ah, but Caesar was an honorable man and Sue never is wrong.

I was wrong when I predicted you would give up on the
absurd twins myth within a year. :-(

"The [ ] Incompatibility of the Law of Propagation of
Light with the Principle of Relativity [is only] Apparent"
http://www.bartleby.com/173/7.html

So 'light always travels at c' is compatible with 'the principle of
relativity'. SR rules [within its domain]. What else is new? Why do
you continue to cite that quotation as if it showed a problem with
SR?

That is a bit hard to see if you model Newton's light bullets
but if you use Maxwell's equations, which Einstein was
defending anyway, it works just fine.

Why do you insist on rejecting Maxwell's equations?

I have nothing against Maxwell's equations.
Where do they say that travel through Minkowski time-space will force
both the stationary twin (be it muon or hu-muon) and the traveling twin
to end up traveling the same distance, time-wise, even though they have
travailed different paths space-time wise (or unwise)?

There are certain path dependent integrals and this is one such.



Einstein changed his explanation of the differential aging from that
in t
he
1905 paper but I do not see anywhere that he abandoned the
differential aging.

See the chapter on Minkowski space. He attaches the imaginary
operator which you can pull out of the equations for wave impedance.

It may be complex, but the fact the operator involves the 'i' axis does
not make the time any less real.

It is just a convenient way of expressing a complex number.

You seem to think that 'imaginary' means 'unreal' in this
context. It does not.

No I don't *seem* to think that because I showed where
the i goes in and where the j comes out. It is plain vanilla
trigonometry.

My mother was from Missouri, show me how the use of i as a convenience for
working with vectors (tensors).

The fact that i allows easy polar/rectangular coordinate conversions
results in something that is quite real and measurable.

What makes you think it is unreal?

Unreal, as opposed to using sqrt(-1) which, although called 'imaginary', is
also quite real, as in shockingly real.

Just take two connected wires carrying a High DC current through a large
inductor, take one wire in each hand and break the connection between the
two wires. The 'i' and 'j' are quite real, no matter how imaginary you
imagine they are].


.....

See Carol here:
http://uw.physics.wisc.edu/~wonders/Van_derr_Graaff4
Her hair is coming out at the roots and she isn't even
moving yet.

You may get a charge out of such citations and pictures but they do not
effect the path taken through space-time. Travel at high velocity DOES
effect the path.

Normally I would ask 'high velocity wrt what body'. But
your statements elsewhere reveal you are assuming
an inertial ether and calling it 'space-time'.

Actually, I thought we were referencing everything to Terra's body.

You have been sniffing ether if you think I am relying on an inertial
aether.

I believe you have studied enough about Einstein's
relativity to know such assumptions are equivalent
to completely rejecting the theory.

LET me at whom every says I am in favor of any aether theory.

The fact remains that you "can't get there from here" while traveling
vast distances in very short times without traversing a different total
amount of time than if you had traveled no distance and ended at the
same space-time coordinates, if you have a well integrated
personality(or even if you don't have any personality, as in the case
of the muons).

And advanced or retarded waves do not make Stella's hair any more or
less chic when it remains dark while her stay at home sister has
tell-tail-grey.

Stella doesn't use this as an inertial ether.
http://farside.ph.utexas.edu/teaching/em/lectures/node113.html

You shouldn't ether... ahh... either.

I don't.




--
bz

please pardon my infinite ignorance, the set-of-things-I-do-not-know is an
infinite set.

bz+spr@xxxxxxxxxxxxxxxxxxxx remove ch100-5 to avoid spam trap
.

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