Re: Can anyone draw a simulation of two orbiting planets?

On Sep 3, 5:18 pm, "gu...@xxxxxxxxxxx" <gu...@xxxxxxxxxxx> wrote:
On Sep 3, 4:07 pm, Randy Poe <poespam-t...@xxxxxxxxx> wrote:



On Sep 3, 3:51 pm, "gu...@xxxxxxxxxxx" <gu...@xxxxxxxxxxx> wrote:

On Sep 2, 10:11 am, Randy Poe <poespam-t...@xxxxxxxxx> wrote:

On Sep 2, 4:46 am, "gu...@xxxxxxxxxxx" <gu...@xxxxxxxxxxx> wrote:

On Sep 1, 3:24 pm, Igor <thoov...@xxxxxxxxxx> wrote:

On Aug 31, 4:53 am, "gu...@xxxxxxxxxxx" <gu...@xxxxxxxxxxx> wrote:

Can anyone draw (perhaps animated gif) a simulation of two orbiting
planets of SAME MASS?

I cannot image how two same mass orbits would look like? ....would
they propagate forward or remain in one constant region?

One location, which doesn't seem to make sense, says: "Since stars
have about the same mass (within a factor of 20), they both orbit
around a common point, called the center of mass, that is
significantly different from one of the star's center.".

(http://www.astronomynotes.com/starprop/s10.htm)

No objects ever orbit around any other objects. All objects will
orbit a common center of mass under gravitational interaction.

Wonder if an atom's nucleus would also have such properties.

No, since (as you have been told many times) an electron
is not in a little Keplerian orbit around the nucleus.

- Randy- Hide quoted text -

1. There is an attraction between the nucleus and the electrons

Yes.

2. They call them orbitals

Yes, that is the name given to different states of the
energy quantum number.

They are not called "orbits", because they are not
orbits.
That's why they were given a different name.

3. These orbitals are circular or elliptical in shape

No, they aren't.

Don't make up physics.

- Randy- Hide quoted text -

#1. The s p d f orbitals are spherical (or elliptical) or donut (ring)
in shape, and one has to define what is ment by a "lower" shell or
lower energy STATE when a photon is released.

The s-orbitals are spherical. The others are not. Nor
are they elliptical. Nor are they "donut-shaped".

#2. Search everywhere and you will find that: It is not that no orbits
exist, instead no "FIXED" orbit exist (meaning the orbits are
probabilisticly located within a region).

No, no orbits exist. This model was inconsistent with
electromagnetic theory. Search everywhere.


#3. Same years as 1925's Heisenberg and 1927's Shrodinger's
probabiltiy equation, in 1925 Uhlenbeck and Goudsmit showed that
***************MANY************* features of atomic spectra (Moseley's
x-ray spectra) can be explained by "assuming" that an electron not
only ****REVOLVES**** around a nucleus but as well the electron has a
property called spin (inherent spin is attribuable to particle more
than wave = rotation of an electron about it's "OWN" axis).

An electron in an orbit would not be in a stable orbit.
It would emit energy and the orbit would decay.

- Randy

.

Relevant Pages

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