Re: "How Does Light 'Know' How Fast to Travel?"
- From: John Kennaugh <JKNG@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx>
- Date: Tue, 4 Sep 2007 17:24:20 +0100
bz wrote:
faJohn Kennaugh <JKNG@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx> wrote in
news:6PboZQGjgR3GFwNV@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx:
The first order effect is the same as acoustic Doppler where the source
is always what moves never the observer.
False. Either the source or the observer may be in motion. Doppler depends
on relative velocity of source and observer.
Go back to your O-level physics. The equation for source moving and observer moving are different. The general equation is:
f = fo(c+vo)/(c-vs)
vo = velocity of the observer relative to the air.
vs = velocity of the source relative to the air.
The equation relevant to SR is the one where the observer is always stationary w.r.t the propagation medium (vo=0). The MMX showed that the observers speed relative to the aether is always zero. The second postulate describes what an observer stationary w.r.t the aether will experience.
Rest snipped.
--
John Kennaugh
.
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