Re: "How Does Light 'Know' How Fast to Travel?"

"John Kennaugh" <JKNG@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx> wrote in message
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bz wrote:
faJohn Kennaugh <JKNG@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx> wrote in
news:6PboZQGjgR3GFwNV@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx:

The first order effect is the same as acoustic Doppler where the source
is always what moves never the observer.


False. Either the source or the observer may be in motion. Doppler depends
on relative velocity of source and observer.

Yes .. for light, not for sound.

Go back to your O-level physics. The equation for source moving and
observer moving are different.

For sound, yes. Not for light in SR .. you only need the relative velocity
between observer and source

The general equation is:

f = fo(c+vo)/(c-vs)

vo = velocity of the observer relative to the air.
vs = velocity of the source relative to the air.

The equation relevant to SR is the one where the observer is always
stationary w.r.t the propagation medium (vo=0).

SR makes no mention of propogating medium. The thing is, that the speed of
light is c for all non-accelerated observers .. so the numerator in that
formula (which is the velocity relative to the observer) will be c .. not c
+ v.

The MMX showed that the observers speed relative to the aether is always
zero.

No .. it doesn't say anything about an aether. You are misrepresenting the
results.

The second postulate describes what an observer stationary w.r.t the
aether will experience.

More misrepresenting . SR says nothing about any aether, it certainly
doesn't say the observer is stationary wrt any aether, and doesn't say that
SR postulate only apply when an observer is stationary relative to an
aether.

I think you need to go back and re-read what SR actually does say :)



.

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