Re: Path in Schwarzschild

On Sep 17, 4:01 pm, JanPB <film...@xxxxxxxxx> wrote:
On Sep 17, 12:22 pm, Koobee Wublee wrote:

No, what you are saying is utterly nonsense. With a single set of
coordinate system, each solution or metric must describe a different
and independent set of geometry. You have been told this for at least
two years.

"Single set of coordinate system"? Is this supposed to mean something?

Of course. Have you not been reading what I wrote to you?

"Each solution or metric must describe a different and independent set
of geometry"? Is this English?

OK, my English literature teacher,

Each solution or metric must describe a different and independent
geometry based on the already established coordinate system.

How is that? Better?

Einstein's equation is a tensor equation (a _single_ tensor equation).

I don't know what you mean by Einstein's equation. Do you mean the
Einstein tensor? Talking about the abuse of vocabulary, you are even
worse than I. <shrug>

Although the Riemann, the Ricci, and the Einstein tensors are called
tensors, for all the mathematical purposes applicable, they are mere
matrices. <shrug>

Its solutions are _tensors_. Only when one writes its coordinate (or
moving frame) components separately does one obtain 16 regular PDEs.

I have told you so before that these 16 partial differential equations
are only valid with the initially chosen coordinate system. Thus, all
the solutions must be referencing to this coordinate system.

In the Schwarzschild's case the solution tensor is unique.

In doing so, the Schwarzschild metric cannot be unique. PERIOD.

Each solution is unique and independent of each other. <shrug>

There is only one tensor that solves Einstein's equation in this case.

I find more than one, and I have shown them to you already. 2 of them
are asymptotically flat, but 2 are not. This negates Birkhoff's
theorem. <shrug>

Yes, it is physical enough to someone outside the event horizon.
<shrug>

So just watching it makes it physical? And coordinates - which are man-
made labels - influence physical events, right? I see.

Do you not understand the time dilation business? I guess not.

He is frozen in time relative to other observers outside of the event
horizon. <shrug>

Only in a certain coordinate sense. In other coordinates (Eddington-
Finkelstein - the standard "pop-sci book coordinates") he is not
frozen. Look it up!

Oh, great. Now, you are claiming a choice of coordinate system would
change the geometry.

Black holes only exist in a few of the solutions to the field
equations. <shrug>

Point is Schwarzschild's solution exhibits it and it's the only
solution in this case.

Schwarzschild's original solution does not exhibit this black hole
nonsense. <shrug>

Don't know basic mathematics?

What makes you ask me this question? Haven't you read my posts before?

Oh, yes. I have read your postings and your biography, and I wish I
had not. That is how I find out you are no mathematician but a
mathemaGician. <shrug>

.

Relevant Pages

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