Re: Sagnac Threads United
- From: "Paul B. Andersen" <paul.b.andersen@xxxxxxxxxxxxxxxx>
- Date: Fri, 02 Nov 2007 11:42:36 +0100
Dr. Henri Wilson wrote:
On Thu, 01 Nov 2007 21:24:29 +0100, "Paul B. Andersen"
<paul.b.andersen@xxxxxxxxxxxxxxx> wrote:
Dr. Henri Wilson skrev:On Wed, 31 Oct 2007 15:22:03 +0100, "Paul B. Andersen"
Indeed.A photon goes through one 'cycle' when it traverses a distance equal to one ofFrequency = angular frequency/2piViewed from the rotating frame, light is being emittedLight doesn't have a 'frequency'. It has a wavelength.
at different frequencies in the forwards and reverse
directions! Forwards light is being emitted with a
frequency of (c+v)/l, while reverse light is being
emitted with a frequency of (c-v)/l.
The conventional frequency associated with light is inferred as the 'number of
wavecrests ariving per second'.
Angular frequency = (d/dt)phase(t)
its absolute wavelengths. This is irrespective of its 'speed', ..which is very
logical since speed is relative to the observer.
And the numbers of such cycles per time unit are different
for your two photons emitted from the same source.
No, the same number of cycles is present in both rays.
What you have to realise is that the startpoint of each cycle moves with the
source. The program shows only ONE emission point of the leading edge of a
photon. The next start point occurs when the source has moved anticlockwise a
short distance. ..so in the source frame, there is always the same number of
'wavelengths' in each path. Count them....
This is funny at best.
So why am I not amused?
Yawn.
--
Paul
http://home.c2i.net/pb_andersen/
.
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