Re: GR1916 question about g=1?

On Nov 16, 12:37 pm, JanPB <film...@xxxxxxxxx> wrote:

In the paper g<0, and Einstein observes that - given the complete
freedom of coordinate choice - one may choose to restrict the
coordinates to those with g=-1 (or sqrt(-g)=+1) if such restriction
brings some rewards (simplified calculations in this case).

This is total nonsense. g is the metric. It is merely a matrix. It
is not a scalar. What g = -1 means is that the determinant of g is
-1. <shrug>

and that setting g=-1,
was a technique to simplify the GR math. (?), but I
don't fully understand it.

It's just that g=constant implies its derivatives are zero so certain
formulas simplify.

You even understand less than Mr. Tucker. <shrug> However, both of
you are so opinionated. That seems to be the only trait in common
between you two. <shrug>


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