Re: GR1916 question about g=1?



On Sat, 17 Nov 2007 01:48:31 -0800 (PST), "Ken S. Tucker"
<dynamics@xxxxxxxxxxxx> wrote:

On Nov 16, 2:19 pm, Koobee Wublee <koobee.wub...@xxxxxxxxx> wrote:
...
On page 180, equation 47 shows exactly what the Ricci tensor is
reduced to with the determinant of g being -1.

LOL, what happens in Eq.(44) to the S_uv if we
permit "g" to be positive and a function of
velocity, such as g = +(1-v^2) ?

What "happens" is that the person who made such a statement is
revealed to be a collosal idiot who doesn't understand that the metric
tensor is a symmetric object containing the ten direction cosines of
that particular coordinate basis which cannot be a function of
velocity.









.



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