Re: GR1916 question about g=1?



On Sat, 17 Nov 2007 11:28:29 -0800 (PST), "Ken S. Tucker"
<dynamics@xxxxxxxxxxxx> wrote:

On Nov 17, 3:51 am, Eric Gisse <jowr.pi.nos...@xxxxxxxxxxxxxxxx>
wrote:
On Sat, 17 Nov 2007 01:48:31 -0800 (PST), "Ken S. Tucker"

<dynam...@xxxxxxxxxxxx> wrote:
On Nov 16, 2:19 pm, Koobee Wublee <koobee.wub...@xxxxxxxxx> wrote:
...
On page 180, equation 47 shows exactly what the Ricci tensor is
reduced to with the determinant of g being -1.

LOL, what happens in Eq.(44) to the S_uv if we
permit "g" to be positive and a function of
velocity, such as g = +(1-v^2) ?

What "happens" is that the person who made such a statement is
revealed to be a collosal idiot who doesn't understand that the metric
tensor is a symmetric object containing the ten direction cosines of
that particular coordinate basis which cannot be a function of
velocity.

Sorry "E" for Eric, it's PEER reviewed,
and found free of error by REAL experts.
I do suggest you keep up your "bake sale"
vocation, you're headed for burger flippin'
Ken

You were the one suggesting a metric that was a function of velocity.
Not Einstein, not anyone else.

Stop pretending you understand anything.
.



Relevant Pages

  • Re: GR1916 question about g=1?
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  • Re: GR1916 question about g=1?
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    (sci.physics.relativity)
  • Re: GR1916 question about g=1?
    ... On Nov 17, 3:51 am, Eric Gisse ... reduced to with the determinant of g being -1. ... permit "g" to be positive and a function of ... velocity. ...
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  • Re: GR1916 question about g=1?
    ... permit "g" to be positive and a function of ... velocity. ... you're headed for burger flippin' ... Please STOP posting to my threads! ...
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  • Re: GR1916 question about g=1?
    ... reduced to with the determinant of g being -1. ... LOL, what happens in Eq.to the S_uv if we ... permit "g" to be positive and a function of ...
    (sci.physics.relativity)