Re: how does an atom emit white depolarized incoherent light?

On Nov 21, 7:03 pm, "OG" <o...@xxxxxxxxxxxxxxxxxxx> wrote:
"tyui" <r9yuh...@xxxxxxxxxx> wrote in message

news:09ad4816-e40b-418c-9a54-6cd7b77d620d@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

a thin wire of pure wolfram irradiate white light

but how is this possible same size atoms to emit
different and normal distributed light?

Because you only get line emission when each atom is
effectively isolated from each other.

Pauli's exclusion principle applies to connected atoms,
which means that no two electrons can share exactly the
same quantum states.

As a result of this, you don't get the distinct
'energy levels' that you hear about in when science is
taught to 16 year-olds.

There's no need to invoke QM principles here. Here is
a useful analogy to offer newbies the next time this
question is asked:

Consider the clear ringing sound of a small bell. Analyze
the output frequencies, and you see a fundamental plus a
limited number of distinct harmonics.

Now throw the bell into a box with hundreds of other
identical bells and shake. Instead of a clear ringing
sound, you get a cacophony.

The analogy between an isolated tungsten atom and
interacting tungsten atoms in a wire should be evident.

(Speaking over OG's shoulder)
May I ask, tyui, what is your native language?
One very seldom finds element 74 referred to as "wolfram"
in English, although "wolfram" is common in other
Germanic languages. Just curious...
http://elements.vanderkrogt.net/elem/w.html

Jerry
.