Re: GR1916 question about g=1?

On Nov 22, 6:58 am, John C. Polasek wrote:
On Wed, 21 Nov 2007, Koobee Wublee wrote:

The above equation is the same as

ds^2 = g_ij dq^i dq^j = [g] * [dq^2]

The last term is wrong. Learn the matrix rules of conformability.
In the first place, if [g] is 4x4 and [dq2] is 4x1 then ds2 = 4x1, a
vector, but you need a scalar.

[dq^2] is a 4-by-4 matrix with (dq^i dq^j) being the elements. How in
the world can you possibly construe [dq^2] as a 4-by-1 matrix?

[Learning deficient remarks snipped]


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