Re: The real twin paradox.
- From: colp <colp@xxxxxxxxxxxxx>
- Date: Thu, 22 Nov 2007 18:26:36 -0800 (PST)
On Nov 23, 3:06 pm, Cosmik de Bris
<cosmik.deb...@xxxxxxxxxxxxxxxxxxxxx> wrote:
colp wrote:
On Nov 23, 2:30 pm, Cosmik de Bris
<cosmik.deb...@xxxxxxxxxxxxxxxxxxxxx> wrote:
colp wrote:
On Nov 23, 1:52 pm, Cosmik de BrisWe, Dirk, Bryan, me, are only trying to help you understand, but you
<cosmik.deb...@xxxxxxxxxxxxxxxxxxxxx> wrote:
colp wrote:What you and Dirk think I need is irrelevant.
On Nov 23, 11:44 am, Cosmik de BrisAs Dirk has told you, and I have told you in the other newsgroup, you
<cosmik.deb...@xxxxxxxxxxxxxxxxxxxxx> wrote:
colp wrote:A circle is perfectly symmetrical.
On Nov 23, 3:18 am, "harry" <harald.vanlintelButNotT...@xxxxxxx>Nothing is ever perfectly symmetrical,
wrote:
"colp" <c...@xxxxxxxxxxxxx> wrote in messageThose arguments depend on the asymmetry of the original thought
news:43e6b051-fef5-444c-a97c-2f5500b8ca1e@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
On Nov 22, 5:48 am, "Josef Matz" <josefm...@xxxxxxxx> wrote:http://math.ucr.edu/home/baez/physics/Relativity/SR/TwinParadox/twin_...
<snip>
Hello DirkA solution could include an argument from general relativity as well,
If you could mathematically demonstrate that the time delays of the
symmetric clock A as viewed by B can be
compensated somehow you have solved the paradox !
Would you tell us idiots how this runs in SR ?
since the twins must spend time in non-inertial frames in order to
accelearate/decelerate and turn around. I don't think it would solve
the paradox though because the dilation effects can be increased
arbitrarily by extending the amount of time spent in inertial frames.
http://en.wikipedia.org/wiki/Twin_paradox
experiment. Since asymmetry is absent in the thought experiment
descriped in the OP, they do not solve the paradox described in this
thread.
how far out of symmetrical doesA finite distance.
something have to be before it becomes asymmetrical?
Nothing magicalThe paradox of the symmetric twins does not depend on magic.
happens when the thought experiment becomes symmetrical, how can it?
The paradox depends of the fact that (according to SR) a twin will
observe the other clock slowing down and never observe it speeding up,
and yet it must tell the same time as his own clock at the end of the
experiment.
need to learn some basics.
just don't want to know. Your poor understanding is the problem. What
you think are marvelous arguments are naiive. You think we can't answer
your questions and therefore we don't know anything, but your questions
are bordering on silly.
Why are you unable to explain the paradox?Because there isn't one.
By paradox I mean a proposition which contains an internal
contradiction.
The proposition is described in the opening post. The contradiction is
that SR says that a twin sees the other clock showing an earlier time
than his clock at the end of the experiment, while symmetry says that
the twin sees both clocks showing the same time.
For the symmetrical case which you seem to think is miraculous in some
way, SR says that the clocks will read the same at the end of the
experiment.
Like I said, the paradox of the symmetric twins does not depend on
magic (or miracles).
You say they won't.
Wrong. I say that the results are contradictory.
SR says that they won't read the same from the frame of reference of
one of the twins.
.
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