Re: What is the " ACTUAL " length ?
- From: kenseto <kenseto@xxxxxxxxxx>
- Date: Sun, 3 Feb 2008 11:11:05 -0800 (PST)
On Feb 1, 3:57 pm, PD <TheDraperFam...@xxxxxxxxx> wrote:
On Feb 1, 1:15 pm, kenseto <kens...@xxxxxxxxxx> wrote:
On Jan 31, 12:07 pm, PD <TheDraperFam...@xxxxxxxxx> wrote:
On Jan 30, 8:58 am, kenseto <kens...@xxxxxxxxxx> wrote:
On Jan 29, 12:53 pm, PD <TheDraperFam...@xxxxxxxxx> wrote:
4. The fact that it fires its rocket at the turn around is irrelevant.
Really? Why is it irrelevant when the rocket is fired to leave B? It
wasn't irrelevant when the rocket is fired to leave A. Why is it
relevant in one case and not the other?
It is irrelevant that the rocket fires its engine at the turn around
at B's location. this will change its state of absolute motion to an
unknown value.
Why is it unknown. It is firing its rocket and accelerating away from
B. It's relative speed with respect to B increases as a result of this
firing, so you know it is accelerating.
Sigh....the ship must turn around at the B location before it fires
its rocket toward the original station A. These maneuvers make the
firing a deceleration action.
Ken, let's be plain.
Monday afternoon, the rocket is parked on A. Its relative speed with
respect to A is 0 km/s and its speed with respect to B is 22 km/s,
because B is receding relative to A.
assuming that B was also launched from A, then B has a higher state of
absolute motion than A.
Tuesday morning, the rocket fires its engine, leaving A and
accelerating toward B. This action *raises* the relative speed of the
rocket with respect to A from 0 km/s to 24 km/s. This same action
*lowers* the speed relative to B from 22 km/s to 2 km/s.
After launch the rocket will have a higher state of absolute motion
than A and after the acceleration it will also have a higher state of
absolute motion than B.
Wednesday afternoon, the rocket turns around and fires its rocket to
slow down its approach to B for a landing. This action *lowers* the
speed relative to B from 2 km/s to 0 km/s. This same rocket firing
*lowers* the speed relative to A from 24 km/s to 22 km/s, because the
rocket is now sitting on B, and B is receding from A at that speed.
This maneuver will lower the rocket's state of absolute motion to that
of B but it will still have a higher state of absolute motion than A.
Friday afternoon, the rocket fires its engine again, leaving B and
accelerating toward A. This action *raises* the relative speed of the
rocket with respect to B from 0 km/s to 24 km/s. This same action
*lowers* the speed relative to A from 22 km/s to 2 km/s.
The rocket fires in the direction of B--->A and this is deceleration
and thus it will lower its state of absolute motion wrt B. But it will
still have a higher state of absolute motion than A.
Sunday morning, the rocket turns around and fires its rocket to slow
down its approach to A for a landing. This action *lowers* the speed
relative to A from 2 km/s to 0 km/s. This same action *lowers* the
speed relative to B from 24 km/s to 22 km/s, because the rocket is now
sitting again on A, and A is receding from B at that speed.
This maneuver will enable the rocket to have the same state of
absolute motion as A.
Ken Seto
.
- Follow-Ups:
- Re: What is the " ACTUAL " length ?
- From: Jeckyl
- Re: What is the " ACTUAL " length ?
- From: PD
- Re: What is the " ACTUAL " length ?
- References:
- Re: What is the " ACTUAL " length ?
- From: kenseto
- Re: What is the " ACTUAL " length ?
- From: PD
- Re: What is the " ACTUAL " length ?
- Prev by Date: Re: I got stuck on Part II of Special Theory of Relativity (by Albert Einstein) textbook, please help
- Next by Date: Re: Are there any civil anti-relativists?
- Previous by thread: Re: What is the " ACTUAL " length ?
- Next by thread: Re: What is the " ACTUAL " length ?
- Index(es):
Relevant Pages
|
