Re: What is Proper Time?
- From: The Ghost In The Machine <ewill@xxxxxxxxxxxxxxxxxxxxxxx>
- Date: Tue, 4 Mar 2008 05:21:11 -0800
In sci.physics.relativity, Artful
<artful@xxxxxxxxxx>
wrote
on Mon, 3 Mar 2008 09:31:59 +1100
<13sman6q2357a8f@xxxxxxxxxxxxxxxxxx>:
"Dr. Henri Wilson" <HW@....> wrote in message
news:hq9ms3dd3f4g71kkundoq22qtb4qd495ds@xxxxxxxxxx
On Sun, 02 Mar 2008 22:39:29 +0100, "Paul B. Andersen"
<paul.b.andersen@xxxxxxxxxxxxxxx> wrote:
Dr. Henri Wilson skrev:
If a clock that reads 12:00:00 EVERYWHERE, even though other observers
are not
immediately aware of the fact, then it is universally 12:00:00
everywhere.
"a clock that reads 12:00:00 EVERYWHERE" is indeed a funny notion. :-)
An omnipresent clock?
No, it is relatively simple to acheive this. ...just use my 'instantaneous
universe' concept....(an infinite array of pre-synched clocks)
They will only remain be synchronized in the frame of reference where they
are all at rest.
If one assumes an array of presynchronized clocks in
accordance with a preferential frame, then, in this frame
(or a frame immobile thereto), one can pick an arbitrary
point as the origin, and then work with circles (or
intervals) of increasing radii, leading to a series of
pulses (L, -L/c) (where (x,t) is an event) from clock L
(which is conveniently L units distant, for an L > 0).
The moving observer will see this as (Lg-vLg/c, -Lg/c-vLg/c^2)
= (Lsqrt(1-v/c)/sqrt(1+v/c), -(L/c)sqrt(1+v/c)/sqrt(1-v/c))
or (L/j, -Lj/c) from the Lorentz, where I'm using the ad
hoc j = sqrt(1+v/c)/sqrt(1-v/c), and g = 1/sqrt(1-v^2/c^2)
= 1/(sqrt(1+v/c)sqrt(1-v/c)).
In the other direction, one can also see a series of pulses
(-L,-L/c) in the frame at rest, leading to
(-Lsqrt(1+v/c)/sqrt(1-v/c), -(L/c)sqrt(1-v/c)/sqrt(1+v/c))
as expected.
Since sqrt(1+v/c)/sqrt(1-v/c) != 1 unless v = 0, the L-clock
will not be in sync with either the zero-clock (the clock
at the arbitrary origin) or the user's own clock, according
to SR.
In nBat theory, where light travels at c' = c-v, the clocks
will indeed be in sync.
I'm not sure what BaTH predicts. In BaTH, c' = c-v only
near the moving source; light eventually travels c' = c
far from the source. The transition formula is (at least
to me) unknown; the most logical one would be a variant
of c' = c-v*exp(-d*k), where d is the distance between
source and observer at the time of the pulse, and k is
a constant.
Not that this would work all that well either.
--
#191, ewill3@xxxxxxxxxxxxx
Useless C/C++ Programming Idea #40490127:
for(;;) ;
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- Re: What is Proper Time?
- From: Paul B. Andersen
- Re: What is Proper Time?
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