Re: invariance of negative signature of the metric?



To all, FLASH!!!
Dr. Tucker, who is located at a secret
and remote location, has been over-
whem'd with emails from all over the
globe confirming the 3,4,5 triangle
and it does indeed confirm General
Relavity's Principle of Covariance!!!!

Ladies & Gentlemen, Dr. Tucker's newest
insight is regarded as the greatest
breakthough since Einstein predicted
light would bend by gravity.

((Dr.Tucker requests that all the
women coming forward to be impregnated
by Dr.Tucker should take a number)).

Dr.Tucker may make a statement soon.
Ken

On Mar 11, 9:17 pm, "Ken S. Tucker" <dynam...@xxxxxxxxxxxx> wrote:
To all,
To improve the presentation of *mathematical
physics*, Dr. Tucker, in the post below,
provides an exceptionally insightful means
to an important aspect of geometry, that
any serious student can do for themselves,
with the described apparatus.

With a rare flash of genius, Dr. Tucker
provides the reader with an apparatus and
the ability to prove the transformation
relating imaginary orthogonal Coordinate
Systems to real nonorthogonal CS's, herein.

On Mar 11, 8:49 pm, "Ken S. Tucker" <dynam...@xxxxxxxxxxxx> wrote:



h^2 = x^2 + y^2

x=5, y=sqrt(-9),

and in that CS k, x,y are orthogonal and
h = 4,

or in a nonorthogonal CS k',

x'=5,y'=3,h'=4.

and now swap x' and h' to get CS K,

X=4,Y=3,H=5 .

What was the question again?
Oh, yeah, signature in CS k is (+,-)
signature in k' is (+,+), and I don't
give a poop about the sig in CS K,
because I'm happy with either k or k'.

Cut out a 3,4,5 triangle, place it on
graph paper, and learn how to transform
complex orthogonal CS's to nonorthogonal
CS's.

Once again Dr, Tucker uses advanced
technology to *experimentally* prove
the General Theory of Relativity's
Principle of Covariance.

Actually when I learned transforming
from the GR vanilla orthogonal signature
(+---) , to the nonorthogonal signature
(++++), in Eq.(9) herein,

http://physics.trak4.com/modern-spacetime.pdf

there was a fair amount of geometric tedium.

The above example allows &y'/&y = sqrt(-1).

Regards
Ken S. Tucker
.



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