Re: Mach's principle and aether

On Mar 14, 9:56 am, "Sue..." <suzysewns...@xxxxxxxxxxxx> wrote:
On Mar 14, 9:52 am, Tom Roberts <tjroberts...@xxxxxxxxxxxxx> wrote:





Sue... wrote:
On Mar 13, 11:36 am, Tom Roberts <tjroberts...@xxxxxxxxxxxxx> wrote:
Sue... wrote:
On Mar 12, 11:36 pm, Tom Roberts <tjroberts...@xxxxxxxxxxxxx> wrote:
Nobody expects SR to be a good model of the world we inhabit. After
all, it is only a LOCAL APPROXIMATION to a much better theory, GR.
When my clock is slower than yours but your clock is slower than
mine ABSURD seems a better description than APPROXIMATE.
The only absurdity is in YOUR statement, not SR. SR in no way implies
"my clock is slower than yours but your clock is slower than mine".

What SR actually says, for an appropriate physical situation, is: you
MEASURE my clock to run slower than yours, and I MEASURE your clock to
run slower than mine; the difference in our MEASUREMENT PROCEDURES makes
this happen, and makes it not be a contradiction. Basically we are
measuring different things, and this difference is inherent when
measuring the rate of a moving clock.

I see.   The word MEASURE makes all the difference.

No. Please re-read what I wrote.

Your post is devoid of any details to justfy distinguishing
a MEASURMENT from a measured quantity on both first and
second readings.

It is the fact that the two observers
use different MESUREMENT PROCEDURES that makes this not be a
contradiction (each observer uses the same procedure, inverting "me" and
"you", which makes their procedures overall be different).

Then your measurement procedure is flawed.

If the muzzle velocity of a rifle is 300 m/sec in one
IRF then it must be 300 m/sec in another IRF.

<< The key to understanding special relativity is
Einstein's relativity principle, which states that:

"All inertial frames are totally equivalent for the
performance of all physical experiments."

In other words, it is impossible to perform a physical
experiment which differentiates in any fundamental
sense between different inertial frames. >>
"The relativity principle"http://farside.ph.utexas.edu/teaching/jk1/lectures/node7.html

In
particular, you cannot measure the rate of a moving clock without having
TWO synchronized clocks at rest in your frame (and vice-versa for the
other frame). This asymmetry of using two clocks to measure the rate of
a single moving clock, is what generates the difference in rates.

Nonsense!

If the clocks and rods in the above example don't both show
a muzzle velocity of 300 m/sec then you have found a violation
of the PoR.



If you would STUDY what SR actually is, rather than using a comic-book
approach, you might actually LEARN something.

It is not clear which person you equate with an author of
comic books

It is YOUR APPROACH that is appropriate for comic books, not scientific
writings.

You are arguing that:

~All inertial frames are NOT totally equivalent for the
performance of all physical experiments.~

We might find that in some comic-book or work of fiction.

Sue...

 <shrug>


Two cars have a closing speed of v. The occupants of each car measure
their own speed to be zero and that of the other car to be v. They do
not agree with each other but they are both correct.

With the clocks, relative simultaneity means the clocks in the other
frame are always out of sync. The individual clocks all tick at the
same rate. If two clocks at the same point read zero, and then you
compare times with another clock in the moving system, they cannot
read the same. We know that the second clock was out of sync with the
first and that the clocks have both been ticking at one proper second
per second since meeting up with the first clock.

An observer in the moving frame finds the exact same thing when he
does the exact same thing in his frame.

In the above example I used two clocks in the moving frame because we
know they are out of sync while ours are in sync. But to those in the
moving frame our clocks are out of sync.

Bruce




Tom Roberts- Hide quoted text -

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