Re: Derivation of Heisenberg Uncertainty from Kaluza Klein Geometry

<EdgarOwen@xxxxxxx> wrote in message
news:a3c0447b-b0b6-47b0-a1d5-9f62c1f242af@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
.. . .

Hi Jay,

I'm glad you didn't take my comments above as criticisms (as some
others did) somehow attempting to invalidate your theory which I have
very high regard for. I certainly think it deserves publication. And
beauty and elegance and explanatory capacity (which yours seems to
have in abundance) are certainly valid criteria for any theory.

[Jay -- my editor is not producing the > for prior text]
Not at all. Constructive critique / queries are what help me dig deeper
into the theory.
[end Jay]

I would like to take issue with your comments "... One question of
interest is whether the
three ordinary space dimensions run through the center of the loop
(at
the origin) or make contact with part of the loop itself in which
case
the point of contact may be specified by theta = +/- 0, 2pi, 4pi,
6pi. .
.. The former circumstance yields a symmetry in that all points on
the
loop are equal; the latter in a sense breaks the symmetry so that one
particular point on the loop -- the point of contact with the
ordinary
dimensions of spacetime -- is special."

I think the proper view here is that every point on the loop must
intersect the other 3 space dimensions (and the time dimension). If
there is no intersection (through the center of the loop) then they
cannot be part of the same space as they are not connected. And of
course it must be every point on the loop that intersects all the
other dimensions, not just a single point. That would be like saying
the x dimension only intersects the y dimension at a single point
which is of course incorrect.

[Jay]
Edgar, I believe you are correct. Thanks for helping me straighten out
a problem I have been tossing around in my mind for the past couple of
weeks.
Best,
Jay.
[end Jay]


Best,
Edgar



.

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