Re: time intervals

On Mar 30, 9:54 pm, rbwinn <rbwi...@xxxxxxxx> wrote:
On Mar 30, 11:46 am, PD <TheDraperFam...@xxxxxxxxx> wrote:



On Mar 29, 10:40 pm, rbwinn <rbwi...@xxxxxxxx> wrote:

On Mar 29, 6:31 pm, Eric Gisse <jowr...@xxxxxxxxx> wrote:

On Mar 29, 2:38 pm, rbwinn <rbwi...@xxxxxxxx> wrote:

On Mar 29, 2:14�pm, Eric Gisse <jowr...@xxxxxxxxx> wrote:> On Mar 29, 10:17�am, rbwinn <rbwi...@xxxxxxxx> wrote:
[snip]

This relates to the Galilean transformation equations in the following
way.

� � � � � � � � � � x'=x-vt
� � � � � � � � � � cn'=ct-vt
� � � � � � � � � � � n'= t(1-v/c)

There is no "c" in Galilean transformations.

There is no "n" in Galilean transformations.

There is if I put them there.
Robert B. Winn

Nope. They are not Galilean transformations if you do.- Hide quoted text -

Well, then go ahead tell us what you think they are, Eric.
Robert B. Winn

Winnian transformations. Claim them. They're unique to you.

PD- Hide quoted text -

- Show quoted text -

Well, really, they are just Galilean transformation equations.  My
part of it just shows a clock running at a different rate than t'=t.
Robert B. Winn

Which is contradictory to the Galilean transformation. What is so
difficult to understand?
.

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