Re: time dilation
- From: rbwinn <rbwinn3@xxxxxxxx>
- Date: Tue, 15 Apr 2008 07:27:55 -0700 (PDT)
On Apr 15, 2:27�am, "harry" <harald.vanlintelButNotT...@xxxxxxx>
wrote:
"rbwinn" <rbwi...@xxxxxxxx> wrote in message
Darwin 123 is a scientist who responded to my post. �He had the idea
of dropping two clocks. �I really like this idea because it shows the
basic difference between the ideas of scientists and my own ideas.
The scientific interpretation is that the picture taken from S will
show the S clock hitting the floor and the S' clock still in the air
showing less time than the S clock. �The picture taken from S' will
show the S' clock hitting the floor and the S clock still in the air
showing less time than the S' clock.
No. Due to the limited speed of light and the conventionality of one-way
lightspeed, a picture taken of two objects with one object far behind the
other such as in your example cannot really show what happened when - as
people became aware of by the end of the 19th century - this became known as
"local time" and "relativity of simultaneity". Such pictures can only "show"
it by convention; that is, by assuming that the speed of light is isotropic
in their frame of choice. In other words, such pictures themselves only show
that the sequence depends on one's assumptions/choice of reference frame.
See also Wikipedia: "Relativity of simultaneity".
� I get a different result. �Using the Galilean transformation
equations and Einstein's idea for constant light speed we have
� � � � � � � � � �x'=x-vt
� � � � � � � � � �y'=y
� � � � � � � � � �z'=z
� � � � � � � � � �t'=t
� �Scientists say that the speed of light measures the same according
to a cesium clock in S' as measured by a cesium clock in S. �Since t'
is already defined to be t in the Galilean transformation equations,
we cannot use t' to show time on a cesium clock in S'. �We have to use
a different variable n'.
� � � � � � � � � w=velocity of light
� � � � � � � � � x=wt
� � � � � � � � � x'=wn'
� � � � � � � x'=x-vt
� � � � � � � �wn'=wt-vt
� � � � � � � � n'=t(1-v/c)
� � �My result for this experiment is that a picture taken from
either frame of reference will show both clocks hitting the floor
simultaneously, and both pictures will show less time on the S' clock.
Robert B. Winn
You are free to reinvent 19th century theory. Just be aware that pictures
cannot provide the information that you claim they do, and that 19th century
theory has been disproved one century ago.
It is not really difficult to overcome your objections. All that
needs to be done is to give the clock released at the top of the train
car momentum that cancels the motion of the train so that it falls
straight to the floor as seen by an observer in S. Even scientists of
today would recognize that in frame of reference S', it takes a clock
falling in a curved path the same amount of time to hit the floor as a
clock falling straight to the floor relative to S'. What is
significant is what S sees. He sees the clock in the train car fall
straight down relative to S and strike the floor at the same time as a
clock in frame of reference S. The clock will also read the same time
as the clock in S.
I can see why you scientists were so worried about these clocks
and did not want them dropped. Galileo was a lot smarter than modern
scientists were giving him credit for.
Robert B. Winn
.
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