Re: An Electron Structure?

On Apr 14, 1:09 pm, "Ken S. Tucker" <dynam...@xxxxxxxxxxxx> wrote:
On Apr 14, 12:20 pm, "Dirk Van de moortel" <dirkvandemoor...@ThankS-NO-



SperM.hotmail.com> wrote:
Ken S. Tucker <dynam...@xxxxxxxxxxxx> wrote in message
4f4a0e85-2047-4121-a695-f2421acab...@xxxxxxxxxxxxxxxxxxxxxxxxxxx

On Apr 13, 2:48 am, "Ken S. Tucker" <dynam...@xxxxxxxxxxxx> wrote:
Some corrections follow,

On Apr 12, 4:43 pm, "Ken S. Tucker" <dynam...@xxxxxxxxxxxx> wrote:

On Apr 12, 1:39 pm, "Ken S. Tucker" <dynam...@xxxxxxxxxxxx> wrote:
On Mar 1, 3:17 pm, "Ken S. Tucker" <dynam...@xxxxxxxxxxxx> wrote:

[snip]

Regards
Ken S. Tucker

[snip]

Regards
Ken S. Tucker

Well, they say if you don't like animals, how can you like people?
Dirk Vdm

I wouldn't like people except wife won't let me,
so I gave the neighbours dog a weiner yesterday.

Assuming my arithmetic is correct, (I'm using
Purcell's E&M pg.12, Eq.(7) to obtain the energy
stored in the three charge configuration), he
recommends using cgs - esu units.

Although I used "numeralogy", to obtain the
dimensions, it proves to me that we can store
energy electrically in very small dimensions,
that has an apparent electrical charge of one,
and a *finite* structure, below what we are able
to currently detect.
That is a definitely required 1st step to research
the electron as a structure.

I used Angular Momentum = Energy*(v/c)*x, (#)
a (v/c) ~ .1285 produces hbar/2, in the
above electron structure.
That uses x=10^-20 cm. and further assumes
the Mass-Energy is concentrated in the two
negative charges. The Mass ~ 9.11*10^28 gm,
c = 3*10^10 cm/sec.

(#) I'm uncertain if that is the correct equation,
any input would be helpful.
I employed E=mc^2 for energy and for the angular
momentum L, used, p=mc*v , L=p*x , from
the 4-momentum.

Anyway, if necessary, I think I can boost to
relativistic speeds and masses and readjust
things, to provide a model for the conjecture
of a finite electron structure.
Thanks fella's
Ken S. Tucker

On Apr 14, 1:09 pm, "Ken S. Tucker" <dynam...@xxxxxxxxxxxx> wrote:
....

- Hide quoted text -
- Show quoted text -
Assuming my arithmetic is correct, (I'm using
Purcell's E&M pg.12, Eq.(7) to obtain the energy
stored in the three charge configuration), he
recommends using cgs - esu units.

Although I used "numeralogy", to obtain the
dimensions, it proves to me that we can store
energy electrically in very small dimensions,
that has an apparent electrical charge of one,
and a *finite* structure, below what we are able
to currently detect.
That is a definitely required 1st step to research
the electron as a structure.

I used Angular Momentum = Energy*(v/c)*x, (#)
a (v/c) ~ .1285 produces hbar/2, in the
above electron structure.
That uses x=10^-20 cm. and further assumes
the Mass-Energy is concentrated in the two
negative charges. The Mass ~ 9.11*10^28 gm,
c = 3*10^10 cm/sec.

(#) I'm uncertain if that is the correct equation,
any input would be helpful.
I employed E=mc^2 for energy and for the angular
momentum L, used, p=mc*v , L=p*x , from
the 4-momentum.

Anyway, if necessary, I think I can boost to
relativistic speeds and masses and readjust
things, to provide a model for the conjecture
of a finite electron structure.
Thanks fella's
Ken S. Tucker

Let's reformulate the "electron structure"
based on an advanced solution to the GR
Field Equations, (Guv=Tuv), (unitivity).

Together with Mr. Diether we created article,
http://physics.trak4.com/GR_Charge_Couple.pdf

Ref to Eq(4), S^2 = X^2 + a*b, Eq(4).

I'll rewrite that more pragmatically as,

X^2 = S^2 - (2*K)*(a*b), Eq(X^2),

where K = G/c^2 and G=Newtons BIG G.

Recapping, I'll refer to the isoceles triangle,
of 3 charges , figuratively presented by,

+

- - FIG1 (as previously posted).

Set the distances between the charges,
S(-,+) = 2* S(-,-) , exactly,

and find the charge configurational energy

E = (-q*-q)/S + 2(-q*+q)/2*S = 0.

In place of S, we'll use a geometry affected
by the presence of the charges above using
Eq.(X^2), to find an energy E', by using X,

E'= q^2/sqrt(1-2Kq^2/s^2)
- 2q^2/sqrt(1+2Kq^2/4s^2),

to obtain the Electron Mass,

E'/c^2 ~ 9.11*10^28 gm

when S~1.818*10^-20 cm.

The above is a much more powerful solution
than numerology because it uses GR's charge
couple (ref'd above) solution to find an
electron structure.
Regards
Ken S. Tucker
.

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