Re: The speed of gravity revisited

On Apr 15, 12:42 pm, "Tom Van Flandern" wrote:

"Koobee Wublee" writes:
[Wublee]: Claiming the speed of gravity exceeding the speed of light in
free space violates relative simultaneity as demanded by the Lorentz
transform and thus SR. Since GR is built on top of SR, GR is falsified in
the process.

Special relativity (SR) has now been falsified in favor of Lorentzian
relativity (LR). See Ref. [1] at end for a primer on LR. The main reasons
for this replacement were published in Ref. [2], and boil down to these two:

REFERENCES:

[1]http://metaresearch.org/cosmology/gravity/LR.asp#_ednref10

Galilean transform (GT):

** dt' = dt
** dx' = dx - v dt
** dy' = dy
** dz' = dz

** dt = dt'
** dx = dx' + v dt
** dy = dy'
** dz = dz'

Lorentzian transform (LR):

** dt' = dt / sqrt(1 - v^2 / c^2)
** dx' = dx
** dy' = dy
** dz' = dz

Lorentz transform (SR):

** dt' = (dt - v dx / c^2) / sqrt(1 - v^2 / c^2)
** dx' = (dx - v dt) / sqrt(1 - v^2 / c^2)
** dy' = dy
** dz' = dz

** dt = (dt' + v dx' / c^2) / sqrt(1 - v^2 / c^2)
** dx = (dx' + v dt') / sqrt(1 - v^2 / c^2)
** dy = dy'
** dz = dz'

As you have correctly pointed out, LR does not manifest the twin's
paradox. However, it manifests the time dilation. In doing so, it
does not satisfy the principle of relativity.

At low speed v, SR reduces to GT, but LR does not. Thus, LR must be
wrong.

The following is a simple way of writing down all the equations of SR.

c^2 dt'^2 - dx'^2 - dy'^2 - dz'^2 = c^2 dt^2 - dx^2 - dy^2 - dz^2

Or

ds^2 = c^2 dt^2 - dx^2 - dy^2 - dz^2

Writing down all the equations of LR into one concise equation, you
have

c^2 dt'^2 - dx'^2 - dy'^2 - dz'^2 = c^2 dt^2 / (1 - v^2 / c^2) - dx^2
- dy^2 - dz^2

Or

ds^2 = c^2 dt^2 / (1 - v^2 / c^2) - dx^2 - dy^2 - dz^2

There is no solution to the field equations that would satisfy your
flat spacetime.

These are very serious flaws to your LR.

LR represents a pile of nonsense just like SR that you've pooh-poohed
and GR that you've embraced. <shrug>


.

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