Re: Principle of equivalence

On Apr 16, 8:43�pm, Bryan Olson <fakeaddr...@xxxxxxxxxxx> wrote:
rbwinn wrote:
Bryan Olson wrote:
rbwinn wrote:
Show the math, Bryan. �The S' clock hits at x=0.
� � � � � � t'=(t-vx/c^2)gamma = t gamma
In order to agree with Galileo's result, t' would have to equal t. �If
you can get t' to equal t, let's see you do it.
Ah, a challenge. That clock, as you said "will be sent opposite the
direction of the motion of the train with a speed relative to S'
that is equal to the speed of the train." Thus in S, the velocity of
that clock is v=0.

� � � � � � �gamma = c / (c**2 - v**2)**(1/2)
� � � � � � �gamma = c / (c**2 - 0)**(1/2)
� � � � � � �gamma = c / (c**2)**(1/2)
� � � � � � �gamma = c / c
� � � � � � �gamma = 1

� � � � � � �t'=(t- v x/c^2) * gamma
� � � � � � �t'=(t- 0 x/c^2) * 1
� � � � � � �t'= t - 0
� � � � � � �t'= t

You challenged me to show "t' would have to equal t". Challenge met.

Well, you did exactly what I said you would do. �You flipped frames of
reference and said the clock was in S.

You claim I "said the clock was in S"? �I try not to say things
quite that vacuous (though I'll admit the showing t'=t was
pretty trivial). All objects are in all frames. One of us says
silly thinks like "the cesium clock in S," but it ain't me.

I did no flipping of frames of reference. Robert, you defined S
as the rest frame.

Figure it from S'.
If you can get it to work from S', I will have to say you have done
something.

In what sense is it not working from S'?

How do you know what the clock is doing relative to S? Only because I
told you. The clock was thrown from S'. How do you figure the time
on the clock from that frame of reference when it hits the floor?

[...]> >>> Well, as I said, if you are correcting papers, just show
the correct
math as you see it.
Done.

I have to give you an incomplete on this one.

Gotta at least pass the course before you can do the grading.

Well, here is how I work the problem.
w=velocity of light
x=wt
x'=wn'
x'=x-vt
wn'=wt-vt
n'=t(1-v/w)

v= velocity of S' relative to S
-v= velocity of clock relative to S'
0 = velocity of clock relative to S

n'=t(1-0/w)
n'=t

Robert B. Winn



.

Relevant Pages

  • Re: Circular motion in SR
    ... runs slower than a clock around which the moving clock is rotating, ... in both frames of reference, does the altitude of the rotating clock ... they put a clock in a satellite and recovered it, ... satellite is the same in both frames of reference. ...
    (sci.physics.relativity)
  • Re: Principle of equivalence
    ... clock from a height equal to the height of the train car roof. ... relativity (which you call the principle of equivalence, ... description of that single sequence as seen from two reference frames, ...
    (sci.physics.relativity)
  • Re: ABOUT THE GALILEI PRINCIPLE OF RELATIVITY
    ... The difference between Galilean transformations and Lorentz ... According to a clock in S, the frame of reference at rest, if you ... frames of reference. ...
    (sci.physics.relativity)
  • Re: Some Contradictory Claims in SR:
    ... >> physical length of a moving ruler is the same as that of the ... we observe that a clock records different elapsed time after a journey. ... >> different length in different frames. ... >> do physics will result different physical laws for different frames. ...
    (sci.physics)
  • Re: The real paradoxes in SR.
    ... So if you really believe that a clock can really ... From different inertial frames of reference .. ... ...it only goes slower, ...
    (sci.physics.relativity)