Re: A Riddle for Relativists.

Dr. Henri Wilson wrote:
On Wed, 14 May 2008 15:44:24 +0200, "Paul B. Andersen"
<paul.b.andersen@xxxxxxxxxxxxxxxx> wrote:

Dr. Henri Wilson wrote:
On Tue, 13 May 2008 11:46:32 +0200, "Paul B. Andersen"
<paul.b.andersen@xxxxxxxxxxxxxxxx> wrote:


So the question is, why is there a specific wavelength
and frequency associated with this hyperfine transition?
Is anything emitted or absorbed when the electron makes the transition?
What?
You are effectively asking why black body radiation occurs at all. It is
random. Electrons are making transitions regularly. To do this they must be
excited by incoming radiation. The same process must apply to the H 21cm line.
A random energy input exites the spin directions to the higher state. Ater a
time, they fall back to their lower state, emitting the 21cm 'photons'.
OK.
So when the electrons fall back to the lower state, photons are emitted.
And this radiation has the wavelength 21 cm and the frequency 1.42 GHz.

It certainly seems like there is a specific wavelength and frequency
associated with the emitted photons, doesn't it? :-)

Ah! Now you are talking. Presumably, an individual photon is emitted with each
transition. I suppose this radiation is detected in a tuned circuit or gas maser. But what
is actually being detected?

So the detected frequency is in the receiver, not in the signal, eh?
You _are_ desperate now, are you not? :-)

One can only speculate on what happens to a large number of such photons that
end up traveling in the same direction of Earth. If they were randomly phased,
they would destructively interfere and no signal would be detected.
So what is your analysis?

Honestly, Henri.
You are not really _this_ stupid, are you?
Or are you? :-)
You probably are.

I will give you a hint.
There is _no way_ two waves which are limited in space
can cancel each other, they will _always_ add.
If you don't agree, tell me where the energy goes.
(Please dispute it. It will be fun. :-) )

If you want to know any more, please look it up somewhere. I don't see that you
are achieving anything by following this line of argument. What is your point?
My point is that Henri Wilson wrote previously:
| .. you still haven't demonstrated that EM radiation of any kind has
| a frequency associated with its basic building blocks...individual photons.
and:
| It measures the frequency of the APPLIED signal...the critical absorption
| frequency. It cannot be assumed that any kind of 'frequency' is emitted as a
| consequence.
and:
| You haven't associated any actual frequency with the emitted photons.

I don't see that this radiation proves your point. You are still claiming that
EM behaves like a 'moving sawblade' ......which has no oscillation.

What I want you to tell me is "WHAT IS ACTUALY RESPONSIBLE FOR THE ANY
SENSATION OF FREQUENCY?"

What the hell are you babbling about?

As you stated yourself, the hyperfine transition emits photons.
Those photons combine to radiation with a very precisely defined
frequency, namely 1,420,405,751.768 Hz. So of course this frequency
is associated with the emitted photons.

Your pretended failure to understand what the frequency
of a common UHF radio wave is, cannot change that.

--
Paul

http://home.c2i.net/pb_andersen/
.

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