Re: Aberrations from the relativistic aberration of light
- From: shalayka@xxxxxxxxx
- Date: Wed, 21 May 2008 10:15:19 -0700 (PDT)
I always thought it worked like this:
1) The speed of light emitted by a source is c, regardless of its
motion. That is, the photon does not move at a velocity of c with
respect to some universal rest frame (how does one even begin to
define such a frame anyway?).
2) Where an observer is moving at a relative velocity v \approx 0.5c
directly away from the source, then a photon emitted directly toward
the observer would approach it at relative velocity of v \approx 0.5c,
increasing the observed wavelength by 2 (half the speed of light,
twice the absorption time, twice the wavelength, half the frequency).
This is where the 1 - cos(\phi) v/c term comes from. The remainder of
the formula is just the kinematic time dilation of the observer.
I take it you're not a fan of relativity.
.
- Follow-Ups:
- Re: Aberrations from the relativistic aberration of light
- From: Androcles
- Re: Aberrations from the relativistic aberration of light
- From: Albertito
- Re: Aberrations from the relativistic aberration of light
- References:
- Aberrations from the relativistic aberration of light
- From: Albertito
- Aberrations from the relativistic aberration of light
- Prev by Date: Aberrations from the relativistic aberration of light
- Next by Date: Re: Aberrations from the relativistic aberration of light
- Previous by thread: Aberrations from the relativistic aberration of light
- Next by thread: Re: Aberrations from the relativistic aberration of light
- Index(es):
Relevant Pages
|