Re: New version of a relativity FAQ

On Jun 21, 8:21 pm, "Pmb" <peter.m.br...@xxxxxxxxxxxxx> wrote:
sniff sniff. I'm getting all misty at the quality of his writing :)

To the author - Well done sir!



Well, you see, Pete if you wanted to do any useful physics, like
calculating the trajectory of a charged particle in a seprator, the
"relativistic mass" is of no use to you, but \gamma*m_0 , where m_0 is
the rest mass and \gamma=1/sqrt(1-(v/c)^2)) is instrumental.

Along the same line, try calculating the mass of a photon gas cloud.

I think that the "new" FAQ article is unfortunately very "retro" :-)
.

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