Re: Are *observed* SR effects real?
- From: "Sue..." <suzysewnshow@xxxxxxxxxxxx>
- Date: Sat, 12 Jul 2008 17:05:43 -0700 (PDT)
On Jul 12, 7:51 pm, Dono <sa...@xxxxxxxxxxx> wrote:
On Jul 12, 4:37 pm, "Sue..." <suzysewns...@xxxxxxxxxxxx> wrote:
On Jul 12, 7:34 pm, Dono <sa...@xxxxxxxxxxx> wrote:
On Jul 12, 4:31 pm, "Sue..." <suzysewns...@xxxxxxxxxxxx> wrote:
On Jul 12, 6:48 pm, Dono <sa...@xxxxxxxxxxx> wrote:
Welcome on board. Looks like you already got yourself one of the more
interesting pathological cases. I hope that you are a psychiatrist,
there is a lot of "study material" :-)
Explain how inertial
motion affects the invariant mass
Explain how inertial
motion affects the invariant mass or torque of this simple
mechanism:
"Torsion Pendulum"
http://farside.ph.utexas.edu/teaching/301/lectures/node139.html
See also:
"The relativity principle"
http://farside.ph.utexas.edu/teaching/em/lectures/node108.html
It doesn't, that's why is called "invariant".
Thank you.
Then its frequency will also be invariant.
No, it won't. Frequency transforms according to T'=\gamma*T .
I know where you are tryng to go, you can't use the Newtonian equation
of motion in order to derive the period T=sqrt(k/I). Besides, in
relativity T=! sqrt(k/I).
<< The key to understanding special relativity is
Einstein's relativity principle, which states that:
All inertial frames are totally equivalent
for the performance of all physical experiments.
In other words, it is impossible to perform a physical
experiment which differentiates in any fundamental
sense between different inertial frames.
By definition,
--> Newton's laws of motion take the same form <--
in all inertial frames. Einstein generalized this result
in his special theory of relativity by asserting that
all laws of physics take the same form in all
inertial frames. >>
http://farside.ph.utexas.edu/teaching/em/lectures/node108.html
Sue...
The reason is that you can no longer start with the Newtonian
equation:
I*d^2(theta)/dt^2=-k*theta because F is not equal to
I*d^2(theta)/dt^2, it is equal to dp/dt.
You are trying to be too clever for your own good.
.
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