Re: The equation x=ct violates the Uncertainty Principle
- From: The TimeLord <math-n-physics-not@xxxxxxx>
- Date: Wed, 03 Sep 2008 06:56:50 -0500
Am Tue, 02 Sep 2008 08:26:55 -0700 schrieb rbwinn <rbwinn3@xxxxxxxx> in
b3c162b1-4f43-4936-99e2-5af01d15dbfd@xxxxxxxxxxxxxxxxxxxxxxxxxxx:
On Sep 1, 11:53�am, The TimeLord <math-n-physics-...@xxxxxxx> wrote:
Am Sun, 31 Aug 2008 08:41:23 -0700 schrieb rbwinn <rbwi...@xxxxxxxx> inw is velocity of light. c is speed of light. If a photon is going in
85c6ca5f-a6f1-4528-8f50-34a8590df...@xxxxxxxxxxxxxxxxxxxxxxxxxx:
On Aug 31, 8:35 am, kenseto <kens...@xxxxxxxxxx> wrote:
The SR .equation x=ct violates the Uncertainty Principle. Why? The
equation implies that the leading edge of a light ray (the first
photon), from a source located at the origin of the x-axis, will hit
a detector on the x-axis a distance from the origin. This means that
the velocity and the position of the first photon is known
simultaneously. This is a violation of the UP.
Ken Seto
I do not know anything about the uncertainty principle, but I have
pointed out before that the equation as Einstein used it should
actually be x=wt where w is the velocity of a photon. �If a photon is
going in
?????
Since x=c*t, you are saying that c=w. Unless you are talking about the
difference in phase velocity and group velocity. In that case there
would be multiple photons. However, I think the kenseto is talking
about monochromatic photons, for which the difference doesn't matter.
the -x direction along the x axis, which according to the Lorentz
equations it could be, then it has a velocity of -c. Robert B. Winn
The Lorentz Transformation doesn't matter in this case.
The only difference I see in that is that w is a vector and c is a
scalar. Other than that, w=c the way you are using it, I think.
the negative direction, its velocity is -c. The Lorentz equations
avoid this problem by having c always squared, since (-c)^2 =c^2.
Mmmmmm, I think you need to study up on Lorentz Transformations.
However, the equation x=ct will not substitute into the Lorentz
equations if x is a negative coordinate. If x is negative, then c has
to be negative or else time is negative. Robert B. Winn
Actually it substitutes fine. The Lorentz Transformation is
x' = gamma * (x - v*t)
t' = gamma * (t - v*x/c^2)
y' = y
z' = z
gamma = 1 / sqrt(1-v^2/c^2)
For the photon with x=c*t, you also have x'=c*t', since the speed of light
in a vacuum is the same for all observers. So
x'/t' = c = (x-v*t)/(t-v*x/c^2)
therefore x-v*t = c*t-v*x/c by cross-multiplying
and since x/t = c we get
(c-v)*t = (c-v)*t
which is consistent for all t and v.
I still don't see how your claim that x=c*t violates the Uncertainty
Principle since *that* is not used here.
--
// The TimeLord says:
// Pogo 2.0 = We have met the aliens, and they are us!
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