Re: answer to YBM's bell problem
- From: rbwinn <rbwinn3@xxxxxxxx>
- Date: Thu, 11 Sep 2008 09:49:39 -0700 (PDT)
On Sep 11, 8:43�am, YBM <ybm...@xxxxxxxx> wrote:
rbwinn a �crit :
On Sep 11, 6:55 am, YBM <ybm...@xxxxxxxx> wrote:
rbwinn a crit :
Speed is the magnitude of velocity. Light has a speed of c fromThis is yours, stupid and disgusting liar.
either direction in either frame of reference. Remember your
equation, YBM?
Well, I think we have a situation like what happened when Gottfried
Leibniz and Sir Isaac Newton both discovered calculus at the same
time. �Who should get credit for it? �Well, I am going to have to
defer and let you take credit for
� � � � � � � n'=t(1-v/w)
n'=t(1-v/w). w is velocity of light. If the light is coming from -a,To show how absurd is your "theory", one only have to write down
it has a velocity of c, if it is coming from a, it has a velocity of -
c. Either way it has a speed of c.
precisely what is implied by you OWN WORDS :
- in order to find a velocity of (c,0,0) for the light ray coming
from (-a,0,0) an observer in B should use a clock giving a
time n'=t(1-v/c)
- in order to find a velocity of (-c,0,0) for the light ray coming
from (a,0,0) an observer in B should use a clock giving a
time n'=t(1+v/c)
You have it exactly right, YBM. �This shows the light from -a and a
meeting at the origin of B at n'=a/c as shown by the n' clock.
Which one : n'=t(1-v/c) or n'=t(1+v/c) ?
Silly : when timing what happens in any experiment an observer needRight. �The observer in A has one clock that shows t, and the observer
only ONE clock.
in B has one clock that shows n'.
Which one : n'=t(1-v/c) or n'=t(1+v/c) ?- Hide quoted text -
- Show quoted text -
Well, if you are talking about an event in B, the n' values would be
the same, and the two t times wouled be different. You have the
reverse effect you see with n' from A. Not to worry, YBM, you have
really discovered a great principle of physics.
Robert B. Winn
.
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