Re: answer to YBM's bell problem

rbwinn a écrit :
On Sep 11, 1:46�pm, YBM <ybm...@xxxxxxxx> wrote:
rbwinn a �crit :

On Sep 11, 11:24 am, YBM <ybm...@xxxxxxxx> wrote:
...
Right. The observer in A has one clock that shows t, and the observer
in B has one clock that shows n'.
Which one : n'=t(1-v/c) or n'=t(1+v/c) ?- Hide quoted text -
Well, if you are talking about an event in B, the n' values would be
the same, and the two t times wouled be different.
Wrong : t(1-v/c) and t(1+v/c) are different except at t=0 (or if v=0).
AGAIN : which n'=t(1-v/c) or n'=t(1+v/c) do you choose ?
They are both correct. � One shows where light from x'= -a is as
compared to a clock in B which shows light to be traveling at a speed
of c, and the other shows where light from x'=a is as compared to a
clock in B which shows light to be traveling at a speed of c if both
beams of light are traveling toward the origin of B. �
If they are "both correct" it means that from the point of view
of B, the events "left light ray arrives at the origin of A" and
"right light ray arrives at the origine of A" have different
time coordinates
� � n'=a/c(1-v/c) for the right one
� � n'=a/c(1+v/c) for the left one
so they don't arrive on A at the same instant (let's forget
for a moment how stupid is to compare events with coordinates
build from clocks being broken first, and broken on a different
way then), so for B, the bell in A don't ring.

Sorry, but it does. This can be proven from the fact that the bell
rings when the origin of B is a distance of vt from the origin of A.
From frame of reference B, when the origin of B is a distance of vt
from the origin of A, the bell at the origin of A rings. That is just
what happens.

This is not what your formulas say. We now have two different
theories from you, both absurd :
The one with formulas, saying that A won't ring as seen in frame B.
The one without formulas, saying that both bells will ring (as seen
by both frames).

Sorry you don't
like where this light is, YBM. �The light will meet at the origin of B
at a time of n'=a/c.
� �Now getting back to the two bells that ring when light from both
directions reaches them, you will notice that from frame of reference
A, the Lorentz equations show only the bell at the origin of A
ringing. �According to your rules, the bell at the origin of B will
not ring.
I say both bells will ring.
????!!!!! You'd better think before writing such absurdities...

Explain how the Lorentz equation show the light turning on the bell at
the origin of B as seen by an observer in A. According to relativity
of simultaneity, the rays of light are not emitted simultaneously in
B. They do not reach the origin of B at the same time. By your own
logic, the bell at the origin of B will not ring.

right. The absurdity is "both bells will ring". BTW, explaining why
it is absurd to say that the ring at the origin of B will ring is
not a job for a physicist but for a physician (or psychiatrist).


.

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